CSES - DatatÃ¤hti 2022 alku - Results
 Task: Ositus Sender: Lexa_ft Submission time: 2021-10-16 19:33:31 Language: PyPy3 Status: READY Result: 0
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groupverdictscore
#10
#20
#30
Test results
testverdicttimegroup
#1ACCEPTED0.04 s1, 2, 3details
#2ACCEPTED0.04 s1, 2, 3details
#30.04 s1, 2, 3details
#40.04 s1, 2, 3details
#50.06 s2, 3details
#60.29 s3details
#7--3details

### Code

```def funct(nu):
return 2**(nu-1)

rawin=input()
wordl=len(rawin)
pp=funct(wordl)
val=pp
dupedict={}
rangdict={}
shr=[]
start=[]
stop=[]
yeetus=0

for i in range(wordl):
x=rawin[i]
if(x in dupedict.keys()):
continue
else:
dlist=[]
n=0
while(True):
m=rawin.find(x,n)
if(m==-1):
break
dlist.append(m)
n=m+1
dupedict[x]=dlist

for ke in dupedict:
dlist=dupedict[ke]
if(len(dlist)>1):
ranges=[]
for i in range(len(dlist)-1):
start.append(int(dlist[i]))
stop.append(int(dlist[i+1]))
ranges.append(stop[-1]-start[-1]+1)
rangdict[ke]=ranges

for i in range(len(start)):
yeetus+=funct(wordl-(stop[i]-start[i]))
for j in range(len(start)):
if(start[j]>start[i] and start[j]<stop[i]):

for k1 in rangdict:
for k2 in rangdict:
if(k1!=k2):
l1=rangdict[k1]
l2=rangdict[k2]
for i in range(len(l1)):
for j in range(len(l2)):
if(l1[i]+l2[j]<=wordl):

print(output)
```

### Test details

#### Test 1

Group: 1, 2, 3

Verdict: ACCEPTED

input
a

correct output
1

user output
1

#### Test 2

Group: 1, 2, 3

Verdict: ACCEPTED

input
abcdefghij

correct output
512

user output
512

Group: 1, 2, 3

Verdict:

input
abcabaacbc

correct output
120

user output
999999871

Group: 1, 2, 3

Verdict:

input
aaxxxxxxaa

correct output
4

user output
999998758

#### Test 5

Group: 2, 3

Verdict:

input
mfyzvoxmppoxcvktmcjkryyocfweub...

correct output
643221148

user output
603711675

#### Test 6

Group: 3

Verdict:

input
weinscqmmpgbrlboocvtbptgbahmwv...

correct output
831644159

user output
461085829

#### Test 7

Group: 3

Verdict:

input
sxaoxcyrjoeieyinaqxwukgzdnhhsw...

correct output
816016015

user output
(empty)