CSES - Datatähti 2022 alku - Results
Submission details
Task:Ositus
Sender:Kirill_Akimov
Submission time:2021-10-14 17:35:26 +0300
Language:Python3 (PyPy3)
Status:READY
Result:0
Feedback
groupverdictscore
#10
#20
#30
Test results
testverdicttimegroup
#1ACCEPTED0.04 s1, 2, 3details
#2ACCEPTED0.04 s1, 2, 3details
#30.04 s1, 2, 3details
#40.04 s1, 2, 3details
#50.04 s2, 3details
#60.06 s3details
#70.25 s3details

Code

string = input()
length = len(string)


symbol = ['', string[0]]

index_of_l = [0, 1] 
index_of_ntl = [0, 0] 

number_for_l = [0, 1]
number_for_ntl = [0, 0] 


count = 2

rightest_ntl = 0



preceding = 1

prime_modulus = 1000000007


for i in range(1, length):


    if string[i-1] == string[i]:

        index_of_ntl[preceding] = index_of_l[preceding]
        index_of_l[preceding] = i
        number_for_ntl[preceding] = number_for_l[preceding]
        continue

    for j in range(1, count):
            
        if string[i] == symbol[j]:


            
            if index_of_ntl[rightest_ntl] > index_of_l[j]:
                index_of_ntl[j] = index_of_l[j]
                index_of_l[j] = i
                number_for_ntl[j] = number_for_l[j]

                
                number_for_l[j] = 2 * number_for_l[preceding]

            elif index_of_l[rightest_ntl] <= index_of_l[j]:
                index_of_ntl[j] = index_of_l[j]
                index_of_l[j] = i
                number_for_ntl[j] = number_for_l[j]

                number_for_l[j] = 2 * number_for_l[preceding] - number_for_ntl[j]
                
                rightest_ntl = j
                
            else:
                index_of_ntl[j] = index_of_l[j]
                index_of_l[j] = i
                number_for_ntl[j] = number_for_l[j]
                
                number_for_l[j] = 2 * number_for_l[preceding] - number_for_ntl[j] + number_for_ntl[rightest_ntl]
                number_for_l[rightest_ntl] -= number_for_ntl[j]
                
                rightest_ntl = j
                    
            if not 0 <= number_for_l[j] < prime_modulus:
                number_for_l[j] %= prime_modulus
                    
            preceding = j
                    
            break


    else:   
        symbol += [string[i]]
            
        index_of_l += [i]
        index_of_ntl += [0]
        
        number_for_l += [2 * number_for_l[preceding]]

        count += 1
        
        if number_for_l[count - 1] > prime_modulus:
            number_for_l[count - 1] %= prime_modulus
        number_for_ntl += [0]
        
        preceding = count - 1


    

print(number_for_l[preceding])

Test details

Test 1

Group: 1, 2, 3

Verdict: ACCEPTED

input
a

correct output
1

user output
1

Test 2

Group: 1, 2, 3

Verdict: ACCEPTED

input
abcdefghij

correct output
512

user output
512

Test 3

Group: 1, 2, 3

Verdict:

input
abcabaacbc

correct output
120

user output
138

Test 4

Group: 1, 2, 3

Verdict:

input
aaxxxxxxaa

correct output
4

user output
3

Test 5

Group: 2, 3

Verdict:

input
mfyzvoxmppoxcvktmcjkryyocfweub...

correct output
643221148

user output
92654766

Test 6

Group: 3

Verdict:

input
weinscqmmpgbrlboocvtbptgbahmwv...

correct output
831644159

user output
892829929

Test 7

Group: 3

Verdict:

input
sxaoxcyrjoeieyinaqxwukgzdnhhsw...

correct output
816016015

user output
654836025