Task: | Tietoverkko |
Sender: | mbezirgan |
Submission time: | 2021-10-17 13:29:20 +0300 |
Language: | C++ (C++17) |
Status: | READY |
Result: | 25 |
group | verdict | score |
---|---|---|
#1 | ACCEPTED | 10 |
#2 | ACCEPTED | 15 |
#3 | TIME LIMIT EXCEEDED | 0 |
test | verdict | time | group | |
---|---|---|---|---|
#1 | ACCEPTED | 0.01 s | 1, 2, 3 | details |
#2 | ACCEPTED | 0.36 s | 2, 3 | details |
#3 | TIME LIMIT EXCEEDED | -- | 3 | details |
Code
#include <iostream> #include <string> #include <vector> #include <memory> // In my opinion this should be the answer as this is BY far the fastest possible but oh well #if 0 inline uint32_t SumFactorial(uint32_t n) { uint32_t a = 0; for (uint32_t i = 1; i < n; i++) a += i; return a; } static uint32_t* stash; inline uint32_t SumFactorialRev(uint32_t n, uint32_t a) { if (stash[a]) return stash[a]; uint32_t b = 0; for (uint32_t i = 0; i < a; i++) b += n - 1 - i; stash[a] = b; return b; } int main() { uint32_t n; std::cin >> n; // Access has to be done using size n and computer id a, b where a is smaller then b as // [b - a - 1 + SumFactorialRev(n, a)] uint32_t* connections = new uint32_t[SumFactorial(n)]; stash = new uint32_t[n](); bool* checked = new bool[n](); uint64_t totalSpeed = 0; // For this to work the fastest way possible the input should be put in order // First input { uint32_t a, b; std::cin >> a; std::cin >> b; a -= 1; b -= 1; uint32_t speed; std::cin >> speed; totalSpeed += speed; uint32_t c1 = a > b ? b : a; uint32_t c2 = a > b ? a : b; connections[c2 - c1 - 1 + SumFactorialRev(n, c1)] = speed; checked[a] = true; checked[b] = true; } for (uint32_t i = 1; i < n - 1; i++) { uint32_t a, b; std::cin >> a; std::cin >> b; a -= 1; b -= 1; uint32_t speed; std::cin >> speed; totalSpeed += speed; uint32_t c1 = a > b ? b : a; uint32_t c2 = a > b ? a : b; connections[c2 - c1 - 1 + SumFactorialRev(n, c1)] = speed; uint32_t cA = checked[a] ? a : b; uint32_t cB = checked[a] ? b : a; // Loop through all known computers for (uint32_t j = 0; j < i + 1; j++) { if (j == cA) continue; c1 = j > cA ? cA : j; c2 = j > cA ? j : cA; uint32_t lowestSpeed = connections[c2 - c1 - 1 + SumFactorialRev(n, c1)]; lowestSpeed = lowestSpeed > speed ? speed : lowestSpeed; c1 = j > cB ? cB : j; c2 = j > cB ? j : cB; connections[c2 - c1 - 1 + SumFactorialRev(n, c1)] = lowestSpeed; totalSpeed += lowestSpeed; } checked[cB] = true; } std::cout << totalSpeed; delete[] connections; delete[] checked; delete[] stash; } #else struct Connection; struct Computer { std::vector<Connection*> connections; }; struct Connection { Computer* other; uint64_t speed; }; uint32_t FindConnectionSize(Computer* computer, Computer* sender) { uint32_t size = 1; for (auto& c : computer->connections) { if (c->other != sender) { size += FindConnectionSize(c->other, computer); } } return size; } void FindAllPaths(uint64_t lowestSpeed, Computer* computer, Computer* sender, uint64_t* speed) { for (auto& c : computer->connections) { if (c->other != sender) { uint64_t loopLowestSpeed = lowestSpeed; if (loopLowestSpeed > c->speed) loopLowestSpeed = c->speed; if (loopLowestSpeed == 1) { if (c->other->connections.size() == 1) *speed += 1; else *speed += FindConnectionSize(c->other, computer); } else { FindAllPaths(loopLowestSpeed, c->other, computer, speed); *speed += loopLowestSpeed; } } } } int main() { uint64_t n; std::cin >> n; Computer* computers = new Computer[n](); Connection* connections = new Connection[2*(n - 1)]; bool* checked = new bool[n](); uint64_t speed = 0; // First input { auto& c1 = connections[0]; auto& c2 = connections[1]; uint64_t a, b; std::cin >> a; std::cin >> b; std::cin >> c1.speed; c2.speed = c1.speed; c1.other = a - 1 + computers; c2.other = b - 1 + computers; computers[a - 1].connections.push_back(&c2); computers[b - 1].connections.push_back(&c1); speed += c1.speed; checked[a - 1] = true; checked[b - 1] = true; } for (uint64_t i = 1; i < n - 1; i++) { auto& c1 = connections[2*i]; auto& c2 = connections[2*i + 1]; uint64_t a, b; std::cin >> a; std::cin >> b; std::cin >> c1.speed; c2.speed = c1.speed; c1.other = a - 1 + computers; c2.other = b - 1 + computers; computers[a - 1].connections.push_back(&c2); computers[b - 1].connections.push_back(&c1); Computer* computer = checked[a - 1] ? c2.other : c1.other; if (c1.speed == 1) { speed += i + 1; } else { FindAllPaths(UINT32_MAX, computer, nullptr, &speed); } checked[computer - computers] = true; } std::cout << speed; delete[] connections; delete[] computers; } #endif
Test details
Test 1
Group: 1, 2, 3
Verdict: ACCEPTED
input |
---|
100 1 2 74 1 3 100 2 4 50 3 5 40 ... |
correct output |
---|
88687 |
user output |
---|
88687 |
Test 2
Group: 2, 3
Verdict: ACCEPTED
input |
---|
5000 1 2 613084013 1 3 832364259 2 4 411999902 3 5 989696303 ... |
correct output |
---|
1103702320243776 |
user output |
---|
1103702320243776 |
Test 3
Group: 3
Verdict: TIME LIMIT EXCEEDED
input |
---|
200000 1 2 613084013 1 3 832364259 2 4 411999902 3 5 989696303 ... |
correct output |
---|
1080549209850010931 |
user output |
---|
(empty) |