Different sums

Create a list that contains the numbers $1 \dots n$ and where each pair of consecutive numbers has a different sum. Any list satisfying the conditions is acceptable.

You may assume that $n$ is in the range $1 \dots 100$.

In a file sumdiff.py, implement a function create that returns the required list.

def create(n):
    # TODO

if __name__ == "__main__":
    print(create(6)) # [3, 1, 6, 2, 4, 5]
    print(create(10)) # [7, 10, 3, 1, 5, 4, 8, 6, 9, 2]
    print(create(15)) # [9, 4, 6, 14, 15, 13, 12, 11, 5, 2, 3, 8, 1, 7, 10]

Explanation: In the code template example $[3,1,6,2,4,5]$, the sums of pairs are $4$, $7$, $8$, $6$ and $9$. Since all the sums are different, the solution is valid. For example the solution $[1,5,2,6,4,3]$ would not be valid, because $5+2=7$ and $4+3=7$.