Pizzat

#include <bits/stdc++.h>
using namespace std;
long long int n,m,k,lasku,vittu;
int main(){
cin>>n>>m>>k;
lasku = (k*m)%n;
vittu = ((k*m)-lasku);
if (lasku!=0 && n!=1&&n!=(k*m)/n) {
	cout<<lasku<<" "<<vittu/(n-1);
}
else {
	cout<<(k*m)/n<<" "<<(k*m)/n;
}
}

Test 1

Verdict: ACCEPTED

Test 2

Verdict: ACCEPTED

Test 3

Verdict: ACCEPTED

Test 4

Verdict: WRONG ANSWER

Test 5

Verdict: WRONG ANSWER

Test 6

Verdict: ACCEPTED

Test 7

Verdict: ACCEPTED

Test 8

Verdict: WRONG ANSWER

Test 9

Verdict: ACCEPTED

Test 10

Verdict: ACCEPTED

Test 11

Verdict: WRONG ANSWER

Test 12

Verdict: WRONG ANSWER

Test 13

Verdict: WRONG ANSWER