Your task is to build a list that contains the child counts of all the nodes in a tree from the smallest to the largest.
For example, in the tree below, the desired list is . The tree has four nodes that have no children. The node has one child, the node has two children, and the node has three children.
In a file children.py
, implement the function count_children
that takes a reference to the root of a tree as parameter and returns the list of child counts.
class Node: def __init__(self, value, children=None): self.value = value self.children = children if children else [] def __repr__(self): if self.children == []: return f"Node({self.value})" else: return f"Node({self.value}, {self.children})" def count_children(node): # TODO if __name__ == "__main__": tree1 = Node(1, [Node(4, [Node(3), Node(7)]), Node(5), Node(2, [Node(6)])]) print(count_children(tree1)) # [0, 0, 0, 0, 1, 2, 3] tree2 = Node(1, [Node(2, [Node(3, [Node(4)])])]) print(count_children(tree2)) # [0, 1, 1, 1] tree3 = Node(1, [Node(2), Node(3), Node(4)]) print(count_children(tree3)) # [0, 0, 0, 3]