You are given a list that consists of the numbers 1 \dots n. A pair of indices (i,j) is an inversion if i<j and the element at index i on the list is greater than the element at index j.
You may assume that n is at most 100.
In a file inversions.py
, implement a function count
that returns the total number of inversions in the list.
def count(t): # TODO if __name__ == "__main__": print(count([1,3,2])) # 1 print(count([1])) # 0 print(count([4,3,2,1])) # 6 print(count([1,8,2,7,3,6,4,5])) # 12
Explanation: The list [4,3,2,1] contains the inversions (0,1), (0,2), (0,3), (1,2), (1,3) and (2,3).