Task: | Järjestys |
Sender: | mangolassi |
Submission time: | 2016-10-03 21:20:09 +0300 |
Language: | C++ |
Status: | READY |
Result: | 100 |
group | verdict | score |
---|---|---|
#1 | ACCEPTED | 19 |
#2 | ACCEPTED | 37 |
#3 | ACCEPTED | 44 |
test | verdict | time | group | |
---|---|---|---|---|
#1 | ACCEPTED | 0.05 s | 1 | details |
#2 | ACCEPTED | 0.05 s | 2 | details |
#3 | ACCEPTED | 0.16 s | 3 | details |
Code
#include <iostream> #include <vector> #include <algorithm> // Augmented binary tree for better average case time complexity. // Hopefully no inputs are inoptimal. I really don't want to make // this a red-black tree. struct Node { int value; int lc; int rc; Node* left; Node* right; Node(int v) { value = v; lc = 0; rc = 0; left = 0; right = 0; } }; struct BinaryTree { Node* root; BinaryTree() { root = 0; } void insert(int i) { Node* node = new Node(i); if (root == 0) { root = node; return; } Node* n = root; while(true) { if (n->value < i) { ++n->rc; if (n->right == 0) { n->right = node; break; } else { n = n->right; } } else if (n->value >= i) { ++n->lc; if (n->left == 0) { n->left = node; break; } else { n = n->left; } } } } int indexOf(int i) { if (root == 0) { return 0; } Node* n = root; int index = 0; while(true) { if (i == n->value) { return index; } if (i < n->value) { n = n->left; } else if (i > n->value) { index += n->lc + 1; n = n->right; } } } }; int main() { int l; std::cin >> l; int* c = new int[l]; for (int i = 0; i < l; ++i) { int n; std::cin >> n; c[i] = n; } /* Insertion sort-ish 0: (a-b)-(c-d)-e-f || Step 1: swap elements before new one's spot 1: (b-a)-(c-d)-e-f || Step 2: swap elements before new one 2: (d-c)-(a-b)-e-f || Step 3: swap elements before new one, and new one 3: e-(b-a)-(c-d)-f || Step 4: Swap elements before new one's spot and the spot 4: (a-b)-e-(c-d)-f || DONE! However, finding the position we need to insert e to is an o(n) operation. So I'll use this augmented binary tree to find the new one's position. */ // Actually you can't swap the first 0 elements :(. I'm removing 1's too since it doesn't cost any extra. std::vector<int> swaps; BinaryTree tree; for (int d = 0; d < l; ++d) { tree.insert(c[d]); int spot = tree.indexOf(c[d]); if (spot > 1) { if (swaps.size() != 0 && swaps[swaps.size() - 1] == spot) { swaps.pop_back(); } else { swaps.push_back(spot); } } if (d > 1) { if (swaps.size() != 0 && swaps[swaps.size() - 1] == d) { swaps.pop_back(); } else { swaps.push_back(d); } } if (d > 0) { if (swaps.size() != 0 && swaps[swaps.size() - 1] == d+1) { swaps.pop_back(); } else { swaps.push_back(d+1); } } if (spot > 0) { if (swaps.size() != 0 && swaps[swaps.size() - 1] == spot+1) { swaps.pop_back(); } else { swaps.push_back(spot+1); } } } std::cout << swaps.size() << "\n"; for (int i = 0; i < (int)swaps.size(); ++i) { std::cout << swaps[i] << " "; } std::cout << "\n"; }
Test details
Test 1
Group: 1
Verdict: ACCEPTED
input |
---|
10 9 3 4 7 6 5 10 2 8 1 |
correct output |
---|
32 10 10 9 10 9 8 7 9 4 2 1 4 5 2... |
user output |
---|
18 4 3 2 4 5 3 2 5 6 3 7 8 6 8 9 ... |
Test 2
Group: 2
Verdict: ACCEPTED
input |
---|
1000 650 716 982 41 133 1000 876 92... |
correct output |
---|
3984 207 207 206 207 128 127 126 12... |
user output |
---|
3963 3 5 2 4 6 7 5 7 8 2 7 8 9 8 3 ... |
Test 3
Group: 3
Verdict: ACCEPTED
input |
---|
100000 94703 47808 62366 31885 7091 8... |
correct output |
---|
399956 98676 98676 98675 98676 62994 ... |
user output |
---|
399892 3 2 3 5 4 5 6 5 4 6 7 5 2 7 8 ... |