Submission details
Task:Download Speed
Sender:aalto26gh_026
Submission time:2026-10-20 19:50:53 +0300
Language:C++ (C++20)
Status:READY
Result:
Test results
testverdicttime
#1ACCEPTED0.00 sdetails
#2ACCEPTED0.00 sdetails
#3ACCEPTED0.00 sdetails
#4ACCEPTED0.00 sdetails
#50.01 sdetails
#6ACCEPTED0.01 sdetails
#7ACCEPTED0.01 sdetails
#8ACCEPTED0.00 sdetails
#9ACCEPTED0.00 sdetails
#10ACCEPTED0.00 sdetails
#110.01 sdetails
#12ACCEPTED0.00 sdetails

Code

#include <iostream>
#include <vector>
#include <queue>
#include <algorithm>

// Ford-Fulkerson
// https://cp-algorithms.com/graph/edmonds_karp.html

using namespace std;

const int INF = 1e9;

int n;

vector<vector<int>> capacity;
vector<vector<int>> adj;

// Find shortest route with capacity left.
// Path doesnt matter, just that it has flow left
int bfs(int s, int t, vector<int>& parent) {
    fill(parent.begin(), parent.end(), -1);
    parent[s] = -2;
    queue<pair<int, int>> q;
    q.push({s, INF});

    // Go thru paths
    while (!q.empty()) {
        int cur = q.front().first;
        int flow = q.front().second;
        q.pop();

        for (int next : adj[cur]) { // Check if it has flow and we havent been there
            if (parent[next] == -1 && capacity[cur][next]) {
                parent[next] = cur;
                int new_flow = min(flow, capacity[cur][next]);
                if (next == t)
                    return new_flow;
                q.push({next, new_flow});
            }
        }
    }

    return 0;
}

// Keep seaching, while capacity remains.
int maxflow(int s, int t) {
    int flow = 0;
    vector<int> parent(n + 1);
    int new_flow;

    // While new flow exists.
    while ((new_flow = bfs(s, t, parent))) {
        // Increase current flow
        flow += new_flow;

        int cur = t;
        while (cur != s) { // Change flow in tree paths
            int prev = parent[cur];
            capacity[prev][cur] -= new_flow;
            capacity[cur][prev] += new_flow;
            cur = prev;
        }
    }

    return flow;
}

int main() {
    int m;
    cin >> n >> m; // N is global

    // Set capacity vector size
    capacity.assign(n + 1, vector<int>(n + 1, 0));
    adj.assign(n + 1, vector<int>());

    // Create tree
    for (int i = 0; i < m; i++) {
        int u, v, c;
        cin >> u >> v >> c;

        // No duplicates
        if (capacity[u][v] == 0 && capacity[v][u] == 0) {
            adj[u].push_back(v);
            adj[v].push_back(u);
        }

        // Set new capacity from queries
        capacity[u][v] += c;
    }

    // Output
    cout << maxflow(1, n) << "\n";

    return 0;
}

Test details

Test 1

Verdict: ACCEPTED

input
4 3
1 2 5
2 3 3
3 4 6

correct output
3

user output
3

Test 2

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 1
2 3 1
2 4 1
...

correct output
2

user output
2

Test 3

Verdict: ACCEPTED

input
4 5
1 2 1000000000
1 3 1000000000
2 3 1
2 4 1000000000
...

correct output
2000000000

user output
2000000000

Test 4

Verdict: ACCEPTED

input
2 1
2 1 100

correct output
0

user output
0

Test 5

Verdict:

input
2 1000
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
1000000000000

user output
-727379968

Feedback: Incorrect character on line 1 col 1: expected "1000000000000", got "-727379968"

Test 6

Verdict: ACCEPTED

input
500 998
1 2 54
1 3 59
1 4 83
2 5 79
...

correct output
60

user output
60

Test 7

Verdict: ACCEPTED

input
500 998
1 2 530873053
1 3 156306296
1 4 478040476
3 5 303609600
...

correct output
1093765123

user output
1093765123

Test 8

Verdict: ACCEPTED

input
2 1
1 2 1

correct output
1

user output
1

Test 9

Verdict: ACCEPTED

input
4 5
1 2 3
2 4 2
1 3 4
3 4 5
...

correct output
6

user output
6

Test 10

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 2
3 2 1
2 4 2
...

correct output
3

user output
3

Test 11

Verdict:

input
10 999
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
111000000000

user output
-669149696

Feedback: Incorrect character on line 1 col 1: expected "111000000000", got "-669149696"

Test 12

Verdict: ACCEPTED

input
7 9
1 2 1
1 3 1
1 4 1
2 5 1
...

correct output
2

user output
2