| Task: | Xor sum |
| Sender: | aalto26dm_025 |
| Submission time: | 2026-09-21 16:30:43 +0300 |
| Language: | C++ (C++20) |
| Status: | READY |
| Result: | ACCEPTED |
| test | verdict | time | |
|---|---|---|---|
| #1 | ACCEPTED | 0.00 s | details |
| #2 | ACCEPTED | 0.60 s | details |
Code
#include <iostream>
#include <vector>
#include <cmath>
#include <bits/stdc++.h>
using namespace std;
int xor_in_range(int a, int b, vector<int> & tree)
{
int n = tree.size() / 2;
a += n; b += n;
int s = 0;
while (a <= b)
{
if (a%2 == 1) s = tree[a++] ^ s;
if (b%2 == 0) s = tree[b--] ^ s;
a /= 2; b /= 2;
}
return s;
}
void add(int k, int x, vector<int> & tree)
{
int n = tree.size() / 2;
k += n;
tree[k] = x;
for (k /= 2; k >= 1; k /= 2)
{
if(tree[2*k+1] != -1) tree[k] = tree[2*k] ^ tree[2*k+1];
else tree[k] = tree[2*k];
}
}
int main()
{
int n_values, n_queries;
cin >> n_values >> n_queries;
int base_array_size = pow(2, ceil(log2(n_values)));
int full_array_size = 2 * base_array_size;
vector<int> segmented_tree(full_array_size, -1);
for(int i = 0; i < n_values; ++i)
{
int temp;
cin >> temp;
add(i, temp, segmented_tree);
}
for(int i = 0; i < n_queries; ++i)
{
int op1, op2;
cin >> op1 >> op2;
cout << xor_in_range(op1 - 1, op2 - 1, segmented_tree) << endl;
}
}Test details
Test 1
Verdict: ACCEPTED
| input |
|---|
| 8 36 7 6 4 6 2 9 4 8 1 1 1 2 1 3 ... |
| correct output |
|---|
| 7 1 5 3 1 ... |
| user output |
|---|
| 7 1 5 3 1 ... |
Test 2
Verdict: ACCEPTED
| input |
|---|
| 200000 200000 921726510 307633388 992247073 ... |
| correct output |
|---|
| 834756431 130379787 403037296 308618218 784778243 ... |
| user output |
|---|
| 834756431 130379787 403037296 308618218 784778243 ... |
