Lukujono

# Checking if it is one should be made more efficient, maybe by keeping track of it is one every time a change to V is made? only needs to be done on division
INCREASE T # 2
INCREASE T
REPEAT X TIMES (
	INCREASE V
)
INCREASE E # Later should be replaced with 1000
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE E
INCREASE Q # Make sure first time runs
REPEAT E TIMES (
	REPEAT Q TIMES (
		CLEAR A
		INCREASE A
		CLEAR B
		CLEAR C
		# Check for divisible by 2, output to X and Y
		REPEAT V TIMES (
			REPEAT A TIMES (
				 CLEAR A
				 INCREASE B
				 INCREASE X
				 CLEAR Y
			)
			REPEAT C TIMES (
				 CLEAR C
				 INCREASE A
				 CLEAR X
				 INCREASE Y
			)
			REPEAT B TIMES (
				 CLEAR B
				 INCREASE C
			)
		)
		#PRINT X
		#PRINT Y
		REPEAT X TIMES ( # pariton, V = 3*V
			REPEAT V TIMES (
				REPEAT T TIMES (
					INCREASE V
				)
			)
			INCREASE V
		)
		REPEAT Y TIMES ( # parillinen, J = V/2
			CLEAR J
			REPEAT V TIMES (
				REPEAT A TIMES (
					CLEAR A
					INCREASE B
					INCREASE J
				)
				REPEAT C TIMES (
					CLEAR C
					INCREASE A
				)
				REPEAT B TIMES (
					CLEAR B
					INCREASE C
				)
			)
			CLEAR V
			REPEAT J TIMES (
				INCREASE V
			)
		)
		#PRINT V
		# Check if it is one, output to Q = 1, if V > 1
		CLEAR O
		CLEAR U
		INCREASE U
		REPEAT V TIMES (
			REPEAT O TIMES ( # Runs on second ( V > 1 ), sets Q = 1
				CLEAR O
				INCREASE Q
			)
			REPEAT U TIMES ( # Runs on first
				CLEAR Q
				INCREASE O
				CLEAR U
			)
		)
		PRINT V
	)
)

Test 1 (public)

Verdict: ACCEPTED