Xor sum

#include <iostream>
 
using namespace std;

const int N = 2e5 + 5;

int n, q;
int x[N];

int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cin >> n >> q;
  for (int i = 1; i <= n; i++) {
    cin >> x[i];
    x[i] ^= x[i - 1];
  }
  while (q--) {
    int a, b;
    cin >> a >> b;
    cout << (x[b] ^ x[a - 1]) << '\n';
  }
  return 0;
}

Test 1

Verdict: ACCEPTED

Test 2

Verdict: ACCEPTED