Kulut

input/code.cpp: In function 'int main()':
input/code.cpp:28:35: warning: narrowing conversion of '(((M - ((int*)(& t))) <unknown operator> 4) + 65)' from 'long int' to 'int' [-Wnarrowing]
   28 |                 r.push_back({(M-t)+'A', (m-t)+'A', maksu});
      |                              ~~~~~^~~~
input/code.cpp:28:46: warning: narrowing conversion of '(((m - ((int*)(& t))) <unknown operator> 4) + 65)' from 'long int' to 'int' [-Wnarrowing]
   28 |                 r.push_back({(M-t)+'A', (m-t)+'A', maksu});
      |                                         ~~~~~^~~~

#include <bits/stdc++.h>
using namespace std;
#define F first
#define S second
typedef long long ll;

int n,t[5],s;
vector<array<int,3>> r;

int main(){
	cin >> n;
	for(int i = 0; i < n; ++i){
		char c; int k; cin >> c >> k;
		t[c-'A'] += k;
		s += k;
	}
	int a = s/4;
	int maksu = 1;
	while(t[0] != t[1] && t[1] != t[2] && t[2] != t[3]){
		int *M = max_element(t,t+4);
		int *m = min_element(t,t+4);
		maksu = a-*m;
		if(*M-maksu < a)
			maksu = *M-a;
		if(!maksu)
				break;
		//cout << (char)(M-t)+'A' << ' ' << (char)(m-t)+'A' << ' ' << maksu << '\n';
		r.push_back({(M-t)+'A', (m-t)+'A', maksu});
		*M -= maksu;
		*m += maksu;
	}
	cout << r.size() << '\n';
	for(auto a : r){
		cout << (char)a[0] << ' ' << (char)a[1] << ' ' << a[2] << '\n';
	}
}

Test 1

Verdict: WRONG ANSWER

Test 2

Verdict: WRONG ANSWER

Test 3

Verdict: WRONG ANSWER

Test 4

Verdict: WRONG ANSWER

Test 5

Verdict: WRONG ANSWER

Test 6

Verdict: WRONG ANSWER

Test 7

Verdict: WRONG ANSWER

Test 8

Verdict: WRONG ANSWER

Test 9

Verdict: WRONG ANSWER

Test 10

Verdict: WRONG ANSWER

Test 11

Verdict: ACCEPTED