CSES - Datatähti 2023 alku - Results
Submission details
Task:Sadonkorjuu
Sender:hoodarm
Submission time:2022-11-09 21:38:24 +0200
Language:Python3 (CPython3)
Status:READY
Result:0
Feedback
groupverdictscore
#10
#20
Test results
testverdicttimegroup
#1ACCEPTED0.02 s1, 2details
#2ACCEPTED0.02 s1, 2details
#3ACCEPTED0.02 s1, 2details
#4ACCEPTED0.02 s1, 2details
#5ACCEPTED0.02 s1, 2details
#6--1, 2details
#7--2details
#8--1, 2details
#9--2details
#10--1, 2details
#11--2details
#12--2details
#13--2details
#14--2details
#15--1, 2details
#16--1, 2details
#17--1, 2details
#18--1, 2details
#19--1, 2details
#20--1, 2details
#21--2details
#22--2details
#23--2details
#24--1, 2details
#25--2details
#26--1, 2details
#27--2details
#28--1, 2details
#29--2details
#30--1, 2details
#31--2details

Code

import math
class FibonacciHeap:
# internal node class
class Node:
def __init__(self, key, value):
self.key = key
self.value = value
self.parent = self.child = self.left = self.right = None
self.degree = 0
self.mark = False
# function to iterate through a doubly linked list
def iterate(self, head):
node = stop = head
flag = False
while True:
if node == stop and flag is True:
break
elif node == stop:
flag = True
yield node
node = node.right
# pointer to the head and minimum node in the root list
root_list, min_node = None, None
# maintain total node count in full fibonacci heap
total_nodes = 0
# return min node in O(1) time
def find_min(self):
return self.min_node
# extract (delete) the min node from the heap in O(log n) time
# amortized cost analysis can be found here (http://bit.ly/1ow1Clm)
def extract_min(self):
z = self.min_node
if z is not None:
if z.child is not None:
# attach child nodes to root list
children = [x for x in self.iterate(z.child)]
for i in range(0, len(children)):
self.merge_with_root_list(children[i])
children[i].parent = None
self.remove_from_root_list(z)
# set new min node in heap
if z == z.right:
self.min_node = self.root_list = None
else:
self.min_node = z.right
self.consolidate()
self.total_nodes -= 1
return z
# insert new node into the unordered root list in O(1) time
def insert(self, key, value=None):
n = self.Node(key, value)
n.left = n.right = n
self.merge_with_root_list(n)
if self.min_node is None or n.key < self.min_node.key:
self.min_node = n
self.total_nodes += 1
return n
# modify the key of some node in the heap in O(1) time
def decrease_key(self, x, k):
if k > x.key:
return None
x.key = k
y = x.parent
if y is not None and x.key < y.key:
self.cut(x, y)
self.cascading_cut(y)
if x.key < self.min_node.key:
self.min_node = x
# merge two fibonacci heaps in O(1) time by concatenating the root lists
# the root of the new root list becomes equal to the first list and the second
# list is simply appended to the end (then the proper min node is determined)
def merge(self, h2):
H = FibonacciHeap()
H.root_list, H.min_node = self.root_list, self.min_node
# fix pointers when merging the two heaps
last = h2.root_list.left
h2.root_list.left = H.root_list.left
H.root_list.left.right = h2.root_list
H.root_list.left = last
H.root_list.left.right = H.root_list
# update min node if needed
if h2.min_node.key < H.min_node.key:
H.min_node = h2.min_node
# update total nodes
H.total_nodes = self.total_nodes + h2.total_nodes
return H
# if a child node becomes smaller than its parent node we
# cut this child node off and bring it up to the root list
def cut(self, x, y):
self.remove_from_child_list(y, x)
y.degree -= 1
self.merge_with_root_list(x)
x.parent = None
x.mark = False
# cascading cut of parent node to obtain good time bounds
def cascading_cut(self, y):
z = y.parent
if z is not None:
if y.mark is False:
y.mark = True
else:
self.cut(y, z)
self.cascading_cut(z)
# combine root nodes of equal degree to consolidate the heap
# by creating a list of unordered binomial trees
def consolidate(self):
A = [None] * self.total_nodes
nodes = [w for w in self.iterate(self.root_list)]
for w in range(0, len(nodes)):
x = nodes[w]
d = x.degree
while A[d] != None:
y = A[d]
if x.key > y.key:
temp = x
x, y = y, temp
self.heap_link(y, x)
A[d] = None
d += 1
A[d] = x
# find new min node - no need to reconstruct new root list below
# because root list was iteratively changing as we were moving
# nodes around in the above loop
for i in range(0, len(A)):
if A[i] is not None:
if A[i].key < self.min_node.key:
self.min_node = A[i]
# actual linking of one node to another in the root list
# while also updating the child linked list
def heap_link(self, y, x):
self.remove_from_root_list(y)
y.left = y.right = y
self.merge_with_child_list(x, y)
x.degree += 1
y.parent = x
y.mark = False
# merge a node with the doubly linked root list
def merge_with_root_list(self, node):
if self.root_list is None:
self.root_list = node
else:
node.right = self.root_list.right
node.left = self.root_list
self.root_list.right.left = node
self.root_list.right = node
# merge a node with the doubly linked child list of a root node
def merge_with_child_list(self, parent, node):
if parent.child is None:
parent.child = node
else:
node.right = parent.child.right
node.left = parent.child
parent.child.right.left = node
parent.child.right = node
# remove a node from the doubly linked root list
def remove_from_root_list(self, node):
if node == self.root_list:
self.root_list = node.right
node.left.right = node.right
node.right.left = node.left
# remove a node from the doubly linked child list
def remove_from_child_list(self, parent, node):
if parent.child == parent.child.right:
parent.child = None
elif parent.child == node:
parent.child = node.right
node.right.parent = parent
node.left.right = node.right
node.right.left = node.left
def dijkstra(adjList, source, sink = None):
n = len(adjList) #intentionally 1 more than the number of vertices, keep the 0th entry free for convenience
visited = [False]*n
distance = [float('inf')]*n
heapNodes = [None]*n
heap = FibonacciHeap()
for i in range(1, n):
heapNodes[i] = heap.insert(float('inf'), i) # distance, label
distance[source] = 0
heap.decrease_key(heapNodes[source], 0)
while heap.total_nodes:
current = heap.extract_min().value
visited[current] = True
#early exit
if sink and current == sink:
break
for (neighbor, cost) in adjList[current]:
if not visited[neighbor]:
if distance[current] + cost < distance[neighbor]:
distance[neighbor] = distance[current] + cost
heap.decrease_key(heapNodes[neighbor], distance[neighbor])
return distance
noOfCities = int (input())
numbers = list(map(int, input().split()))
adjList=[[] for t in range(0,noOfCities+1)]
for i in range(1,noOfCities):
information = list(map(int, input().split()))
adjList[information[0]].append(tuple([information[1],information[2]]))
adjList[information[1]].append(tuple([information[0],information[2]]))
totalshortest = 0
for t in range(1,noOfCities+1):
shortest = math.inf
answer = dijkstra(adjList,t)
for i in answer:
if ((numbers[answer.index(i)-1]==0) and i<shortest):
shortest = i
totalshortest=totalshortest+shortest
print (totalshortest)

Test details

Test 1

Group: 1, 2

Verdict: ACCEPTED

input
1
0

correct output
0

user output
0

Test 2

Group: 1, 2

Verdict: ACCEPTED

input
5
0 0 0 0 0
1 2 1
2 3 2
3 4 3
...

correct output
0

user output
0

Test 3

Group: 1, 2

Verdict: ACCEPTED

input
4
1 0 1 1
1 2 10
2 3 20
2 4 30

correct output
60

user output
60

Test 4

Group: 1, 2

Verdict: ACCEPTED

input
5
0 1 1 1 0
1 2 10
2 3 20
3 4 30
...

correct output
80

user output
80

Test 5

Group: 1, 2

Verdict: ACCEPTED

input
5
0 1 0 1 1
1 2 1
2 3 5
3 4 3
...

correct output
6

user output
6

Test 6

Group: 1, 2

Verdict:

input
1000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
5506363

user output
(empty)

Test 7

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
1795118520

user output
(empty)

Test 8

Group: 1, 2

Verdict:

input
1000
0 0 1 0 1 1 0 1 0 1 1 0 0 0 1 ...

correct output
293576

user output
(empty)

Test 9

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
816932444

user output
(empty)

Test 10

Group: 1, 2

Verdict:

input
1000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

correct output
3089

user output
(empty)

Test 11

Group: 2

Verdict:

input
200000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

correct output
40839

user output
(empty)

Test 12

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
5683983203973

user output
(empty)

Test 13

Group: 2

Verdict:

input
200000
0 1 1 1 1 1 1 0 0 0 1 1 0 1 0 ...

correct output
58572993

user output
(empty)

Test 14

Group: 2

Verdict:

input
200000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

correct output
32755

user output
(empty)

Test 15

Group: 1, 2

Verdict:

input
1000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
126238345

user output
(empty)

Test 16

Group: 1, 2

Verdict:

input
1000
0 0 0 1 0 1 1 1 0 0 1 0 1 1 0 ...

correct output
278678

user output
(empty)

Test 17

Group: 1, 2

Verdict:

input
1000
1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 ...

correct output
34929

user output
(empty)

Test 18

Group: 1, 2

Verdict:

input
1000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
1543963

user output
(empty)

Test 19

Group: 1, 2

Verdict:

input
1000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

correct output
39606

user output
(empty)

Test 20

Group: 1, 2

Verdict:

input
1000
1 0 1 0 1 0 0 0 0 1 1 0 0 0 1 ...

correct output
321598

user output
(empty)

Test 21

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
978670626

user output
(empty)

Test 22

Group: 2

Verdict:

input
200000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

correct output
375218

user output
(empty)

Test 23

Group: 2

Verdict:

input
200000
1 1 1 1 0 0 0 0 0 1 0 1 0 1 1 ...

correct output
60422556

user output
(empty)

Test 24

Group: 1, 2

Verdict:

input
1000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
291990

user output
(empty)

Test 25

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
59607954

user output
(empty)

Test 26

Group: 1, 2

Verdict:

input
1000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
990

user output
(empty)

Test 27

Group: 2

Verdict:

input
200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
199982

user output
(empty)

Test 28

Group: 1, 2

Verdict:

input
1000
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
7987

user output
(empty)

Test 29

Group: 2

Verdict:

input
200000
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
3137875

user output
(empty)

Test 30

Group: 1, 2

Verdict:

input
1000
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
4657693

user output
(empty)

Test 31

Group: 2

Verdict:

input
200000
0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
1652889357

user output
(empty)