Task: | Ruudukko |
Sender: | okkokko |
Submission time: | 2022-11-09 18:19:59 +0200 |
Language: | C++ (C++11) |
Status: | READY |
Result: | 61 |
group | verdict | score |
---|---|---|
#1 | ACCEPTED | 28 |
#2 | ACCEPTED | 33 |
#3 | TIME LIMIT EXCEEDED | 0 |
test | verdict | time | group | |
---|---|---|---|---|
#1 | ACCEPTED | 0.00 s | 1, 2, 3 | details |
#2 | ACCEPTED | 0.00 s | 1, 2, 3 | details |
#3 | ACCEPTED | 0.00 s | 1, 2, 3 | details |
#4 | ACCEPTED | 0.01 s | 2, 3 | details |
#5 | ACCEPTED | 0.01 s | 2, 3 | details |
#6 | ACCEPTED | 0.01 s | 2, 3 | details |
#7 | ACCEPTED | 0.54 s | 3 | details |
#8 | ACCEPTED | 0.64 s | 3 | details |
#9 | TIME LIMIT EXCEEDED | -- | 3 | details |
Code
#include <iostream>#include <vector>#include <unordered_set>#include <set>using namespace std;const int DIVISOR = 1000000007;vector<int> line_row(1000);vector<int> line_row_last(1000);vector<int> line_col(1000);vector<int> line_col_last(1000);vector<int> line_row_added(1000);vector<int> line_col_added(1000);set<tuple<int, int, int>> values_coords;int total = 0;int get_line_row(int y, int v){if (v == line_row_last[y]){return line_row[y];}line_row_last[y] = v;int s;s = (line_row[y] + line_row_added[y]) % DIVISOR;line_row_added[y] = 0;line_row[y] = s;return s;}int get_line_col(int x, int v){if (v == line_col_last[x]){return line_col[x];}line_col_last[x] = v;int s;s = (line_col[x] + line_col_added[x]) % DIVISOR;line_col_added[x] = 0;line_col[x] = s;return s;}int calculate_routes(int y, int x, int number){int value;if (number == 1){value = 1;}else{value = (get_line_col(x, number) + get_line_row(y, number) + 1) % DIVISOR;}total += value;total %= DIVISOR;line_row_added[y] += value;line_row_added[y] %= DIVISOR;line_col_added[x] += value;line_col_added[x] %= DIVISOR;return value;}class Node{// "Binary Search Tree node"public:vector<tuple<int, int>> values;Node *parent;Node *left;Node *right;int key;int marker = 0;bool is_root;bool has_left = false;bool has_right = false;int var_pos;Node(int key_){key = key_;is_root = true;}Node(Node &parent_, int key_){key = key_;parent = &parent_;marker = 0;}Node *next(){if (marker == 0){marker += 1;if (has_left){return left;}}if (marker == 1){marker += 1;if (has_right){return right;}}marker = 0;return parent;}void routes_calc(){for (auto v : values){calculate_routes(key, get<1>(v), get<0>(v));}}};class BST{Node *root;BST(int middle){Node node = Node(middle);root = &node;}void Insert(int key, tuple<int, int> value){Node *node = search(key);if (node->var_pos == 1){Node nod = Node(*node, key);node->left = &nod;node->left->values.push_back(value);node->has_left = true;}else if (node->var_pos == 2){Node nod = Node(*node, key);node->right = &nod;node->right->values.push_back(value);node->has_right = true;}else{node->values.push_back(value);}}void Iter(){Node *node = root;Node *neue;while (true){neue = node->next();if (node == root and node->marker == 0){break;}if (node->marker == 0){// # neue is parentif (neue->marker == 1){// node is leftneue->routes_calc();}}else if (neue->has_left == false){neue->routes_calc();}node = neue;}}Node *search(int key_){// """returns a node and a number.// 0 means the node has the wanted value,// 1 means the value doesn't exist but would be the node's left branch if inserted,// 2 means the same as 1 but for the right branch."""// # no recursionNode *current = root;while (true){if (key_ < current->key){if (current->has_left){current = current->left;}else{current->var_pos = 1;return current;}}else if (key_ > current->key){if (current->has_right){current = current->right;}else{current->var_pos = 2;return current;}}else{current->var_pos = 0;return current;}}}};int main(){int n;cin >> n;vector<vector<int>> grid;// grid.reserve(n * n);for (int i = 0; i < n; i++){vector<int> b;for (int j = 0; j < n; j++){int a;cin >> a;b.push_back(a);}grid.push_back(b);}vector<int> line_row(n, 0);vector<int> line_row_last(n, 1);vector<int> line_col(n, 0);vector<int> line_col_last(n, 1);vector<int> line_row_added(n, 0);vector<int> line_col_added(n, 0);// vector<unordered_set<int>> exists_row;// set<int> exists_all;for (int y = 0; y < n; y++){// unordered_set<int> s;for (int x = 0; x < n; x++){// s.insert(grid[y][x]);// exists_all.insert(grid[y][x]);values_coords.insert(make_tuple(grid[y][x], x, y));}// exists_row.push_back(s);}set<tuple<int, int, int>>::iterator itr;for (itr = values_coords.begin(); itr != values_coords.end(); itr++){calculate_routes(get<2>(*itr), get<1>(*itr), get<0>(*itr));}cout << total << "\n";return 0;}
Test details
Test 1
Group: 1, 2, 3
Verdict: ACCEPTED
input |
---|
3 1 1 1 1 1 1 1 1 1 |
correct output |
---|
9 |
user output |
---|
9 |
Test 2
Group: 1, 2, 3
Verdict: ACCEPTED
input |
---|
3 1 2 3 6 5 4 7 8 9 |
correct output |
---|
135 |
user output |
---|
135 |
Test 3
Group: 1, 2, 3
Verdict: ACCEPTED
input |
---|
3 7 8 1 4 5 4 3 9 6 |
correct output |
---|
57 |
user output |
---|
57 |
Test 4
Group: 2, 3
Verdict: ACCEPTED
input |
---|
100 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ... |
correct output |
---|
10000 |
user output |
---|
10000 |
Test 5
Group: 2, 3
Verdict: ACCEPTED
input |
---|
100 1 2 3 4 5 6 7 8 9 10 11 12 13 ... |
correct output |
---|
187458477 |
user output |
---|
187458477 |
Test 6
Group: 2, 3
Verdict: ACCEPTED
input |
---|
100 2995 8734 1018 2513 7971 5063 ... |
correct output |
---|
964692694 |
user output |
---|
964692694 |
Test 7
Group: 3
Verdict: ACCEPTED
input |
---|
1000 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ... |
correct output |
---|
1000000 |
user output |
---|
1000000 |
Test 8
Group: 3
Verdict: ACCEPTED
input |
---|
1000 1 2 3 4 5 6 7 8 9 10 11 12 13 ... |
correct output |
---|
229147081 |
user output |
---|
229147081 |
Test 9
Group: 3
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 520283 805991 492643 75254 527... |
correct output |
---|
951147313 |
user output |
---|
(empty) |