Kertoma

import math
import sys

def get_amount_of_numbers(x):
	# try to calculate the number of digits in numbers up to x and see if the sum of that is the same as sum of the original numbers

	# because log(a*b) = log(a) + log(b) we can try this:
	ten_exponential = 0
	for i in range(1,x+1):
		ten_exponential += math.log(i, 10)
	# then the number_of_digits = math.floor(ten_exponential) + 1
	return math.floor(ten_exponential) + 1


def factorial(x):
	if x == 1:
		return x
	else:
		return factorial(x-1)*x

def check_original(x):
	string = str(factorial(x))
	numbers = [0]*10
	for i in range(len(string)):
		numbers[int(string[i])] += 1
	return numbers


if __name__=="__main__":
	sys.setrecursionlimit(10000000)

	amount_of_digits = [int(x) for x in str(input()).split(" ")]

	sum_of_all = sum(amount_of_digits)
	x = 0
	while True:
		if get_amount_of_numbers(x) == sum_of_all:
			if check_original(x) == amount_of_digits:
				print(x)
				exit()
		x += 1

	#print(x)

Test 1

Group: 1, 2, 3

Verdict: RUNTIME ERROR

Test 2

Group: 1, 2, 3

Verdict: RUNTIME ERROR

Test 3

Group: 1, 2, 3

Verdict: ACCEPTED

Test 4

Group: 1, 2, 3

Verdict: ACCEPTED

Test 5

Group: 1, 2, 3

Verdict: ACCEPTED

Test 6

Group: 1, 2, 3

Verdict: ACCEPTED

Test 7

Group: 2, 3

Verdict: ACCEPTED

Test 8

Group: 2, 3

Verdict: ACCEPTED

Test 9

Group: 2, 3

Verdict: ACCEPTED

Test 10

Group: 2, 3

Verdict: ACCEPTED

Test 11

Group: 3

Verdict: TIME LIMIT EXCEEDED

Test 12

Group: 3

Verdict: TIME LIMIT EXCEEDED

Test 13

Group: 3

Verdict: TIME LIMIT EXCEEDED

Test 14

Group: 3

Verdict: TIME LIMIT EXCEEDED

Test 15

Group: 3

Verdict: TIME LIMIT EXCEEDED

Test 16

Group: 3

Verdict: TIME LIMIT EXCEEDED