CSES - Datatähti 2023 alku - Results
Submission details
Task:Kertoma
Sender:chaotic
Submission time:2022-11-01 18:29:20 +0200
Language:C++17
Status:READY
Result:100
Feedback
groupverdictscore
#1ACCEPTED22
#2ACCEPTED24
#3ACCEPTED54
Test results
testverdicttimegroup
#1ACCEPTED0.00 s1, 2, 3details
#2ACCEPTED0.00 s1, 2, 3details
#3ACCEPTED0.00 s1, 2, 3details
#4ACCEPTED0.00 s1, 2, 3details
#5ACCEPTED0.00 s1, 2, 3details
#6ACCEPTED0.00 s1, 2, 3details
#7ACCEPTED0.00 s2, 3details
#8ACCEPTED0.00 s2, 3details
#9ACCEPTED0.00 s2, 3details
#10ACCEPTED0.00 s2, 3details
#11ACCEPTED0.00 s3details
#12ACCEPTED0.00 s3details
#13ACCEPTED0.00 s3details
#14ACCEPTED0.00 s3details
#15ACCEPTED0.00 s3details
#16ACCEPTED0.00 s3details

Code

#include <algorithm>
#include <cassert>
#include <cmath>
#include <iostream>
#include <numeric>
#include <vector>

/*
 * Kertoman x! lukujen määrä kasvaa ainakin yhdellä, kun x>10
 * Tiedetään lukujen k määrä
 * floor(log_10(x!) = k - 1
 * log_10(x!) = ln(gamma(x))/ln(10)
 * Joten ln(gamma(x)) = (k-1)*ln(10)
 * Tämä voidaan ratkaista esim. sekanttimenetelmällä
*/

int main() {
    std::vector<int> nums;
    nums.reserve(10);
    for (int i = 0; i < 10; ++i) {
        int v;
        std::cin >> v;
        nums.push_back(v);
    }

    int k = std::accumulate(nums.begin(), nums.end(), 0);

    double result;
    if (k > 4) {
        // Ratkaistaan yhtälö ln(gamma(x)) = (k-1)*ln(10) x:n suhteen

        auto f = [k](double x) { return std::lgamma(x) - (k - 1) * std::log(10); };

        // Sekanttimenetelmällä
        double error = 0;
        double x_n1  = 5;
        double x_n2  = 20;
        for (int i = 0; i < 100; ++i) {
            double x_n = x_n1 - f(x_n1) * (x_n1 - x_n2) / (f(x_n1) - f(x_n2));
            assert(x_n > 0);
            x_n2  = x_n1;
            x_n1  = x_n;
            error = x_n1 - x_n2;
            if (std::abs(error) < 0.01) break;
        }
        result = x_n1;
    } else {
        if (k == 4) result = 7;
        if (k == 3) { result = nums[1] == 1 ? 5 : 6; }
        if (k == 2) result = 4;
        if (k == 1) { result = nums[2] == 1 ? 2 : 3; }
    }

    std::cout << std::floor(result);
}

Test details

Test 1

Group: 1, 2, 3

Verdict: ACCEPTED

input
0 0 1 0 0 0 0 0 0 0

correct output
2

user output
2

Test 2

Group: 1, 2, 3

Verdict: ACCEPTED

input
0 0 0 0 0 0 1 0 0 0

correct output
3

user output
3

Test 3

Group: 1, 2, 3

Verdict: ACCEPTED

input
0 0 1 0 1 0 0 0 0 0

correct output
4

user output
4

Test 4

Group: 1, 2, 3

Verdict: ACCEPTED

input
2 0 1 1 0 0 1 0 2 0

correct output
10

user output
10

Test 5

Group: 1, 2, 3

Verdict: ACCEPTED

input
9 3 1 1 2 2 3 1 6 1

correct output
27

user output
27

Test 6

Group: 1, 2, 3

Verdict: ACCEPTED

input
10 4 3 4 3 2 2 4 3 7

correct output
36

user output
36

Test 7

Group: 2, 3

Verdict: ACCEPTED

input
71 53 36 30 25 29 42 24 34 29

correct output
199

user output
199

Test 8

Group: 2, 3

Verdict: ACCEPTED

input
71 33 46 38 27 45 36 21 35 35

correct output
205

user output
205

Test 9

Group: 2, 3

Verdict: ACCEPTED

input
93 38 35 26 43 54 38 25 41 34

correct output
222

user output
222

Test 10

Group: 2, 3

Verdict: ACCEPTED

input
100 33 33 45 36 43 38 54 56 36

correct output
242

user output
242

Test 11

Group: 3

Verdict: ACCEPTED

input
3419 1797 1845 1849 1879 1791 ...

correct output
5959

user output
5959

Test 12

Group: 3

Verdict: ACCEPTED

input
4776 2695 2709 2781 2616 2753 ...

correct output
8391

user output
8391

Test 13

Group: 3

Verdict: ACCEPTED

input
20097 12282 12229 12214 12406 ...

correct output
32001

user output
32001

Test 14

Group: 3

Verdict: ACCEPTED

input
47934 29918 29878 29713 29984 ...

correct output
71718

user output
71718

Test 15

Group: 3

Verdict: ACCEPTED

input
84691 54156 54277 54533 54296 ...

correct output
123123

user output
123123

Test 16

Group: 3

Verdict: ACCEPTED

input
99098 63339 63878 64182 63904 ...

correct output
142663

user output
142663