sume

#include <iostream>

using namespace std;

int t[1000][1000], A[1000];
int main(){
    int n;
    cin >> n;
    for(int i=0; i<n; ++i)for(int j=0; j<n; ++j) cin >> t[i][j];

    for(int i=1; i<n; ++i){
        A[i]= t[i][(i+1)%n]-t[i-1][(i+1)%n];
    }
    if(n==1){
        cout << t[0][0];
        return 0;
    }else if(n==2){
        cout << "1 1";
        return 0;
    }
    A[0] = (t[0][1]-A[1])/2;
    int s=0;
    for(int i=0; i<n; ++i){
        s+=A[i];
        cout << s << " ";
    }
}

Test 1

Verdict: ACCEPTED

Test 2

Verdict: ACCEPTED

Test 3

Verdict: ACCEPTED

Test 4

Verdict: ACCEPTED

Test 5

Verdict: ACCEPTED

Test 6

Verdict: ACCEPTED

Test 7

Verdict: ACCEPTED