sume

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
int t[1111][1111];;
int main() {
    int n;
    cin>>n;
    ll totSum = 0;
    for(int i = 0; i < n; ++i) {
	for(int j = 0; j < n; ++j) {
	    cin>>t[i][j];
	    totSum += t[i][j];
	}
    }
    ll c = 0;
    for(int i = 0; i < n; ++i) {
	c += t[0][i];
    }
    totSum /= (n-1)*2;
    if(n == 2) {
	cout<<1<<' '<<1<<'\n';
	return 0;
    }
    ll a1 = (-totSum+c)/(n-2);
    cout<<a1<<' ';
    for(int i = 1; i < n; ++i) {
	cout<<t[0][i]-a1<<' ';
    }
    cout<<'\n';
}

Test 1

Verdict: ACCEPTED

Test 2

Verdict: ACCEPTED

Test 3

Verdict: ACCEPTED

Test 4

Verdict: ACCEPTED

Test 5

Verdict: ACCEPTED

Test 6

Verdict: ACCEPTED

Test 7

Verdict: ACCEPTED