Dice Summation

#include <bits/stdc++.h>
using namespace std;

int main () {
    // freopen("input.txt", "r", stdin);

    const int D = 6;
    int ar[D];
    ar[0] = 1;
    
    int n;
    cin >> n;

    for (int i = 1; i <= n; i++) {
        int sum = 0;
        for (int j = 1; j <= D; j++) {
            if (i - j >= 0) sum += ar[(i-j)%D];
        }
        ar[i%D] = sum;
    }

    cout << ar[n%D];

    return 0;
}

Test 1

Verdict: ACCEPTED

Test 2

Verdict: ACCEPTED

Test 3

Verdict: ACCEPTED

Test 4

Verdict: ACCEPTED

Test 5

Verdict: ACCEPTED

Test 6

Verdict: ACCEPTED

Test 7

Verdict: ACCEPTED

Test 8

Verdict: ACCEPTED

Test 9

Verdict: ACCEPTED

Test 10

Verdict: ACCEPTED

Test 11

Verdict: WRONG ANSWER

Test 12

Verdict: WRONG ANSWER

Test 13

Verdict: WRONG ANSWER

Test 14

Verdict: WRONG ANSWER

Test 15

Verdict: WRONG ANSWER

Test 16

Verdict: WRONG ANSWER

Test 17

Verdict: WRONG ANSWER

Test 18

Verdict: WRONG ANSWER

Test 19

Verdict: WRONG ANSWER

Test 20

Verdict: WRONG ANSWER