Skittles

input/code.cpp: In function 'long long int initNCR(long long int, long long int)':
input/code.cpp:70:1: warning: no return statement in function returning non-void [-Wreturn-type]
   70 | }
      | ^

#include <iostream>
#include <vector>
#include <array>
#include <string>
#include <algorithm>
#include <numeric>
#include <unordered_map>
#include <unordered_set>
#include <set>
#include <queue>
#include <climits>
#include <cmath>
#include <functional>
#include <type_traits>
#include <fstream>
#include <bitset>
#include <complex>
#include <iomanip>

#include <ext/pb_ds/assoc_container.hpp> // gcc only
template<typename T>
using ordered_set = __gnu_pbds::tree<T, __gnu_pbds::null_type, std::less<T>, __gnu_pbds::rb_tree_tag, __gnu_pbds::tree_order_statistics_node_update>;
 
#define int long long
using namespace std;
 
#define cross(x, y) (((x)*conj(y)).imag())
#define sign(v) ((0 < (v)) - ((v) < 0))


int mod = 998244353;

int p(int a, int b, int m)
{
    if (b == 0) return 1;
    else if (b % 2 == 0) { int r = p(a, b/2, m); return (r*r) % m; }
    else return (p(a, b-1, m)*a) % m; 
}
int gdc(int a, int b)
{
    if (b == 0) return a;
    return gdc(b, a%b);
}
 
// Works to approx n=60

vector<int> facts;
int startInverse = 1;

int initNCR(int r, int maxN)
{
    facts = vector<int>(maxN+1);
    facts[0] = 1;
    int multiple = 1;
    for (int i = 1; i <= r; i++)
    {
        multiple *= i;
        multiple %= mod;
    }
    facts[r] = multiple;
    for (int i = r+1; i < maxN; i++)
    {
        multiple *= i;
        multiple %= mod;
        multiple *= p(i-r, mod-2, mod);
        multiple %= mod;

        facts[i] = multiple;
    }
}

int fastNCR(int n, int r)
{
    int val = startInverse * facts[n];
    val %= mod;
    return val * p(facts[r], mod-2, mod);
}

int nCr(int n, int r)
{
    int res = 1;
    for (int i = 0; i < r; i++)
    {
        res *= (n-i);
        res *= p(i+1, mod-2, mod);
    }
    return res;
}



void solve()
{
    int n, a, b;
    cin >> n >> a >> b;

    initNCR(n-1, 700010);

    int result = 0;

    for (int i = a; i <= b; i++)
    {
        result += fastNCR(i+n-1, n-1);
        result %= mod;
    }
    cout << result;

}
 
 
signed main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.precision(15);
 
    int t = 1;
 
    //cin >> t;
 
    for (int i = 0; i < t; i++)
    {
        solve();
        //cout.flush();
    }
}

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