Task: | Polygon area |
Sender: | bubu2006 |
Submission time: | 2024-11-11 16:21:57 +0200 |
Language: | C++ (C++20) |
Status: | READY |
Result: | ACCEPTED |
test | verdict | time | |
---|---|---|---|
#1 | ACCEPTED | 0.00 s | details |
#2 | ACCEPTED | 0.00 s | details |
#3 | ACCEPTED | 0.00 s | details |
Code
#include <bits/stdc++.h> using namespace std; #define int long long #define rep(i, a, b) for(int i = a; i < (b); ++i) #define all(x) begin(x), end(x) #define sz(x) (int)(x).size() typedef long long ll; typedef pair<int, int> pii; typedef vector<int> vi; /** * Author: Ulf Lundstrom * Date: 2009-02-26 * License: CC0 * Source: My head with inspiration from tinyKACTL * Description: Class to handle points in the plane. * T can be e.g. double or long long. (Avoid int.) * Status: Works fine, used a lot */ template <class T> int sgn(T x) { return (x > 0) - (x < 0); } template<class T> struct Point { typedef Point P; T x, y; explicit Point(T x=0, T y=0) : x(x), y(y) {} bool operator<(P p) const { return tie(x,y) < tie(p.x,p.y); } bool operator==(P p) const { return tie(x,y)==tie(p.x,p.y); } P operator+(P p) const { return P(x+p.x, y+p.y); } P operator-(P p) const { return P(x-p.x, y-p.y); } P operator*(T d) const { return P(x*d, y*d); } P operator/(T d) const { return P(x/d, y/d); } T dot(P p) const { return x*p.x + y*p.y; } T cross(P p) const { return x*p.y - y*p.x; } T cross(P a, P b) const { return (a-*this).cross(b-*this); } T dist2() const { return x*x + y*y; } double dist() const { return sqrt((double)dist2()); } // angle to x-axis in interval [-pi, pi] double angle() const { return atan2(y, x); } P unit() const { return *this/dist(); } // makes dist()=1 P perp() const { return P(-y, x); } // rotates +90 degrees P normal() const { return perp().unit(); } // returns point rotated 'a' radians ccw around the origin P rotate(double a) const { return P(x*cos(a)-y*sin(a),x*sin(a)+y*cos(a)); } friend ostream& operator<<(ostream& os, P p) { return os << "(" << p.x << "," << p.y << ")"; } }; template<class T> T polygonArea2(vector<Point<T>>& v) { T a = v.back().cross(v[0]); rep(i,0,sz(v)-1) a += v[i].cross(v[i+1]); return a; } signed main() { cin.tie(0)->sync_with_stdio(0); cin.exceptions(cin.failbit); // RTE if input wrong datatype int n; cin >> n; vector<Point<int>> p(n); for (int i = 0; i < n; i++) { cin >> p[i].x >> p[i].y; } int ans = polygonArea2(p); cout << abs(ans); }
Test details
Test 1
Verdict: ACCEPTED
input |
---|
100 -7 -19 91 77 100 100 64 60 ... |
correct output |
---|
43582 |
user output |
---|
43582 |
Test 2
Verdict: ACCEPTED
input |
---|
1000 365625896 -113418831 278762563 38777445 250367343 -96991975 175866909 -129766978 ... |
correct output |
---|
4053466653883387139 |
user output |
---|
4053466653883387139 |
Test 3
Verdict: ACCEPTED
input |
---|
4 -1000000000 -1000000000 -1000000000 1000000000 1000000000 1000000000 1000000000 -1000000000 |
correct output |
---|
8000000000000000000 |
user output |
---|
8000000000000000000 |