CSES - Aalto Competitive Programming 2024 - wk7 Homework - Results
Submission details
Task:Download Speed
Sender:ilyas.ben
Submission time:2024-10-23 15:05:03 +0300
Language:Java
Status:READY
Result:
Test results
testverdicttime
#1ACCEPTED0.13 sdetails
#2ACCEPTED0.13 sdetails
#3ACCEPTED0.14 sdetails
#4ACCEPTED0.13 sdetails
#50.22 sdetails
#6ACCEPTED0.23 sdetails
#7ACCEPTED0.22 sdetails
#8ACCEPTED0.13 sdetails
#9ACCEPTED0.14 sdetails
#10ACCEPTED0.13 sdetails
#110.22 sdetails
#12ACCEPTED0.14 sdetails

Code

import java.util.*;

class MaxFlow {
    private int n;
    private int[][] capacity;
    private List<List<Integer>> adj;

    public MaxFlow(int n) {
        this.n = n;
        capacity = new int[n][n];
        adj = new ArrayList<>(n);
        for (int i = 0; i < n; i++) {
            adj.add(new ArrayList<>());
        }
    }

    public void addEdge(int u, int v, int cap) {
        capacity[u][v] += cap;
        adj.get(u).add(v);
        adj.get(v).add(u);
    }

    private boolean bfs(int source, int sink, int[] parent) {
        boolean[] visited = new boolean[n];
        Queue<Integer> queue = new LinkedList<>();
        queue.offer(source);
        visited[source] = true;

        while (!queue.isEmpty()) {
            int u = queue.poll();
            for (int v : adj.get(u)) {
                if (!visited[v] && capacity[u][v] > 0) {
                    queue.offer(v);
                    visited[v] = true;
                    parent[v] = u;
                    if (v == sink) return true;
                }
            }
        }
        return false;
    }

    public int fordFulkerson(int source, int sink) {
        int maxFlow = 0;
        int[] parent = new int[n];

        while (bfs(source, sink, parent)) {
            int pathFlow = Integer.MAX_VALUE;
            for (int v = sink; v != source; v = parent[v]) {
                int u = parent[v];
                pathFlow = Math.min(pathFlow, capacity[u][v]);
            }
            for (int v = sink; v != source; v = parent[v]) {
                int u = parent[v];
                capacity[u][v] -= pathFlow;
                capacity[v][u] += pathFlow;
            }
            maxFlow += pathFlow;
        }
        return maxFlow;
    }

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt();
        int m = scanner.nextInt();
        MaxFlow maxFlow = new MaxFlow(n + 1);

        for (int i = 0; i < m; ++i) {
            int a = scanner.nextInt();
            int b = scanner.nextInt();
            int c = scanner.nextInt();
            maxFlow.addEdge(a, b, c);
        }

        System.out.println(maxFlow.fordFulkerson(1, n));
        scanner.close();
    }
}

Test details

Test 1

Verdict: ACCEPTED

input
4 3
1 2 5
2 3 3
3 4 6

correct output
3

user output
3

Test 2

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 1
2 3 1
2 4 1
...

correct output
2

user output
2

Test 3

Verdict: ACCEPTED

input
4 5
1 2 1000000000
1 3 1000000000
2 3 1
2 4 1000000000
...

correct output
2000000000

user output
2000000000

Test 4

Verdict: ACCEPTED

input
2 1
2 1 100

correct output
0

user output
0

Test 5

Verdict:

input
2 1000
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
1000000000000

user output
0

Test 6

Verdict: ACCEPTED

input
500 998
1 2 54
1 3 59
1 4 83
2 5 79
...

correct output
60

user output
60

Test 7

Verdict: ACCEPTED

input
500 998
1 2 530873053
1 3 156306296
1 4 478040476
3 5 303609600
...

correct output
1093765123

user output
1093765123

Test 8

Verdict: ACCEPTED

input
2 1
1 2 1

correct output
1

user output
1

Test 9

Verdict: ACCEPTED

input
4 5
1 2 3
2 4 2
1 3 4
3 4 5
...

correct output
6

user output
6

Test 10

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 2
3 2 1
2 4 2
...

correct output
3

user output
3

Test 11

Verdict:

input
10 999
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
111000000000

user output
0

Test 12

Verdict: ACCEPTED

input
7 9
1 2 1
1 3 1
1 4 1
2 5 1
...

correct output
2

user output
2