CSES - Aalto Competitive Programming 2024 - wk7 Homework - Results
Submission details
Task:Download Speed
Sender:Nallue
Submission time:2024-10-19 16:59:21 +0300
Language:C++ (C++11)
Status:READY
Result:
Test results
testverdicttime
#1ACCEPTED0.00 sdetails
#2ACCEPTED0.00 sdetails
#3ACCEPTED0.00 sdetails
#4ACCEPTED0.01 sdetails
#50.00 sdetails
#6ACCEPTED0.01 sdetails
#7ACCEPTED0.02 sdetails
#8ACCEPTED0.00 sdetails
#9ACCEPTED0.00 sdetails
#10ACCEPTED0.00 sdetails
#110.00 sdetails
#12ACCEPTED0.00 sdetails

Code

#include <iostream>
#include <limits.h>
#include <queue>
#include <string.h>
#include <vector>
using namespace std;
 

bool bfs(vector<vector<int>>& rGraph, int s, int t, vector<int>& parent)
{
    int V = rGraph.size();

    vector<bool> visited(V,false);
 
    queue<int> q;
    q.push(s);
    visited[s] = true;
    parent[s] = -1;
 
    while (!q.empty()) {
        int u = q.front();
        q.pop();
 
        for (int v = 0; v < V; v++) {
            if (visited[v] == false && rGraph[u][v] > 0) {
                if (v == t) {
                    parent[v] = u;
                    return true;
                }
                q.push(v);
                parent[v] = u;
                visited[v] = true;
            }
        }
    }
 
    return false;
}

int fordFulkerson(vector<vector<int>> graph, int s, int t)
{
    int u, v;

    int V = graph.size();
 
    vector<vector<int>> rGraph(V,vector<int>(V));

    for (u = 0; u < V; u++)
        for (v = 0; v < V; v++)
            rGraph[u][v] = graph[u][v];


    vector<int> parent(V);
 
    int max_flow = 0; 

    while (bfs(rGraph, s, t, parent)) {
        int path_flow = INT_MAX;
        for (v = t; v != s; v = parent[v]) {
            u = parent[v];
            path_flow = min(path_flow, rGraph[u][v]);
        }
 
        for (v = t; v != s; v = parent[v]) {
            u = parent[v];
            rGraph[u][v] -= path_flow;
            rGraph[v][u] += path_flow;
        }
 
        max_flow += path_flow;
    }
 
    return max_flow;
}
 
int main()
{
    int n,m;
    cin >> n >> m;

    vector<vector<int>> graph(n,vector<int>(n));

    for(int i=0; i<m; i++){
        int a,b,c;
        cin >> a >> b >> c;
        graph[a-1][b-1]=c;
    }
 
    cout << fordFulkerson(graph, 0, n-1) << endl;
 
}

Test details

Test 1

Verdict: ACCEPTED

input
4 3
1 2 5
2 3 3
3 4 6

correct output
3

user output
3

Test 2

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 1
2 3 1
2 4 1
...

correct output
2

user output
2

Test 3

Verdict: ACCEPTED

input
4 5
1 2 1000000000
1 3 1000000000
2 3 1
2 4 1000000000
...

correct output
2000000000

user output
2000000000

Test 4

Verdict: ACCEPTED

input
2 1
2 1 100

correct output
0

user output
0

Test 5

Verdict:

input
2 1000
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
1000000000000

user output
1000000000

Test 6

Verdict: ACCEPTED

input
500 998
1 2 54
1 3 59
1 4 83
2 5 79
...

correct output
60

user output
60

Test 7

Verdict: ACCEPTED

input
500 998
1 2 530873053
1 3 156306296
1 4 478040476
3 5 303609600
...

correct output
1093765123

user output
1093765123

Test 8

Verdict: ACCEPTED

input
2 1
1 2 1

correct output
1

user output
1

Test 9

Verdict: ACCEPTED

input
4 5
1 2 3
2 4 2
1 3 4
3 4 5
...

correct output
6

user output
6

Test 10

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 2
3 2 1
2 4 2
...

correct output
3

user output
3

Test 11

Verdict:

input
10 999
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
111000000000

user output
1000000000

Test 12

Verdict: ACCEPTED

input
7 9
1 2 1
1 3 1
1 4 1
2 5 1
...

correct output
2

user output
2