CSES - Aalto Competitive Programming 2024 - wk7 Homework - Results
Submission details
Task:Download Speed
Sender:snude
Submission time:2024-10-18 16:34:26 +0300
Language:C++ (C++11)
Status:READY
Result:
Test results
testverdicttime
#1ACCEPTED0.00 sdetails
#20.00 sdetails
#30.00 sdetails
#4ACCEPTED0.00 sdetails
#5ACCEPTED0.01 sdetails
#6ACCEPTED0.00 sdetails
#7ACCEPTED0.01 sdetails
#8ACCEPTED0.00 sdetails
#9ACCEPTED0.00 sdetails
#10ACCEPTED0.00 sdetails
#11ACCEPTED0.01 sdetails
#120.00 sdetails

Code

#include <climits>
#include <cmath>
#include <iostream>
#include <vector>

// Debug printing
#ifdef DEBUG
#define deb(fmt, args...) printf("DEBUG: %d: " fmt, __LINE__, ##args)
#else
#define deb(fmt, args...)
#endif

using namespace std;
using ll = long long;

void print_array(vector<int> in, const string title = "Vector")
{
	cout << title << " [\n";
	for (const auto &el : in) {
		cout << el << " ";
	}
	cout << "\n] END\n";
}

void print_matrix(vector<vector<int> > in, const string title = "Matrix")
{
	cout << title << " [\n";
	for (unsigned int i = 0; i < in.size(); i++) {
		cout << "row " << i << ": ";
		for (unsigned int j = 0; j < in[i].size(); j++) {
			cout << in[i][j] << " ";
		}
		cout << "\n";
	}
	cout << "] END\n";
}

ll target;
ll found = true;
vector<ll> path;
bool visited[500];

void dfs(ll s, vector<vector<ll> > &adj, vector<vector<ll> > &edges,
	 vector<ll> &path)
{
	if (found) {
		return;
	}
	if (visited[s]) {
		return;
	};
	visited[s] = true;
	if (s == target) {
		found = true;
		return;
	}

	for (auto u : adj[s]) {
        // ll a = edges[u][0];
        ll b = edges[u][1];
        ll c = edges[u][2];
        // deb("s: %d, a: %d, b: %d, c: %d\n", s, a, b, c);
        if (c > 0) {
            path.push_back(u);
            dfs(b, adj, edges, path);
            if (found) return;
            path.pop_back();
        }
	}
}

void find_cut(vector<ll> &nodes)
{
	for (ll i = 1; i < 501; i++) {
		if (visited[i])
			nodes.push_back(i);
	}
}

int main(int argc, char *argv[])
{
	ll n, m;
	cin >> n >> m;
    target = n;
	// each edge is of form (a, b, c, i)
	vector<vector<ll> > edges(m + 1, vector<ll>(3));
	for (ll i = 1; i < m + 1; i++) {
		cin >> edges[i][0] >> edges[i][1] >> edges[i][2];
	}


	// Add edges to adjacent structure
	// tuple contains target node, residual capacity and edge index
	// each element contains a vector of edges that are adjacent to the node
	vector<vector<ll> > adj(n + 1, vector<ll>());
	for (ll j = 1; j < m + 1; j++) {
		adj[edges[j][0]].push_back(j);
		// adj[edges[j][1]].push_back(j);
	}

	// print_matrix(edges, "edges");
	// print_matrix(adj, "adjacent");

    ll index = 0;
    ll speed = 0;
	while (found) {
		found = false;
		for (ll i = 0; i < n + 1; i++)
			visited[i] = false;

		path.clear();
		dfs(1, adj, edges, path);
        // print_array(path, "path");
		if (found) {
			// add stuff
			ll residual = INT_MAX;
			// find residual capacity of the path
			for (auto e : path) {
				vector<ll> edge = edges[e];
                // deb("ei: %d, c: %d\n", e, edge[2]);
                if (edge[2] < residual) residual = edge[2];
			}
            // deb("res: %d\n", residual);
            speed += residual;

			// update flows
			for (auto e : path) {
				if (e < 0) {
					edges[-e][2] += residual;
				} else {
					edges[e][2] -= residual;
				}
			}
		}
        index++;
	}

    cout << speed << "\n";

	return 0;
}

Test details

Test 1

Verdict: ACCEPTED

input
4 3
1 2 5
2 3 3
3 4 6

correct output
3

user output
3

Test 2

Verdict:

input
4 5
1 2 1
1 3 1
2 3 1
2 4 1
...

correct output
2

user output
1

Test 3

Verdict:

input
4 5
1 2 1000000000
1 3 1000000000
2 3 1
2 4 1000000000
...

correct output
2000000000

user output
1999999999

Test 4

Verdict: ACCEPTED

input
2 1
2 1 100

correct output
0

user output
0

Test 5

Verdict: ACCEPTED

input
2 1000
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
1000000000000

user output
1000000000000

Test 6

Verdict: ACCEPTED

input
500 998
1 2 54
1 3 59
1 4 83
2 5 79
...

correct output
60

user output
60

Test 7

Verdict: ACCEPTED

input
500 998
1 2 530873053
1 3 156306296
1 4 478040476
3 5 303609600
...

correct output
1093765123

user output
1093765123

Test 8

Verdict: ACCEPTED

input
2 1
1 2 1

correct output
1

user output
1

Test 9

Verdict: ACCEPTED

input
4 5
1 2 3
2 4 2
1 3 4
3 4 5
...

correct output
6

user output
6

Test 10

Verdict: ACCEPTED

input
4 5
1 2 1
1 3 2
3 2 1
2 4 2
...

correct output
3

user output
3

Test 11

Verdict: ACCEPTED

input
10 999
1 2 1000000000
1 2 1000000000
1 2 1000000000
1 2 1000000000
...

correct output
111000000000

user output
111000000000

Test 12

Verdict:

input
7 9
1 2 1
1 3 1
1 4 1
2 5 1
...

correct output
2

user output
1