CSES - Aalto Competitive Programming 2024 - wk7 Homework - Results
Submission details
Task:Company Queries II
Sender:Farah
Submission time:2024-10-13 21:00:22 +0300
Language:Python3 (CPython3)
Status:READY
Result:
Test results
testverdicttime
#1ACCEPTED0.02 sdetails
#2ACCEPTED0.02 sdetails
#3ACCEPTED0.02 sdetails
#4ACCEPTED0.02 sdetails
#5ACCEPTED0.02 sdetails
#6--details
#7--details
#8--details
#9--details
#10--details
#11ACCEPTED0.02 sdetails
#12--details

Code

import sys
import sys
def main():
import sys
import sys
from math import log2, ceil
from sys import stdin
data = sys.stdin.read().split()
ptr = 0
n = int(data[ptr]); ptr += 1
q = int(data[ptr]); ptr += 1
# Initialize adjacency list
adj = [[] for _ in range(n + 1)]
# Read bosses for employees 2 to n
for child in range(2, n + 1):
boss = int(data[ptr]); ptr +=1
adj[boss].append(child)
LOG = ceil(log2(n)) if n >1 else 1
up = [[-1]*(n +1) for _ in range(LOG)]
depth = [0]*(n +1)
# BFS to compute depth and up[0][v]
queue = [1]
head = 0
up[0][1] = -1 # root has no parent
while head < len(queue):
node = queue[head]
head +=1
for child in adj[node]:
depth[child] = depth[node] +1
up[0][child] = node
queue.append(child)
# Precompute up tables
for k in range(1, LOG):
for v in range(1, n +1):
if up[k-1][v] != -1:
up[k][v] = up[k-1][up[k-1][v]]
else:
up[k][v] = -1
# Function to find LCA
def lca(a, b):
if depth[a] < depth[b]:
a, b = b, a
# Bring a to the same depth as b
for k in range(LOG-1, -1, -1):
if up[k][a] != -1 and depth[up[k][a]] >= depth[b]:
a = up[k][a]
if a == b:
return a
# Now lift both a and b
for k in range(LOG-1, -1, -1):
if up[k][a] != -1 and up[k][a] != up[k][b]:
a = up[k][a]
b = up[k][b]
return up[0][a]
output = []
for _ in range(q):
a = int(data[ptr]); ptr +=1
b = int(data[ptr]); ptr +=1
output.append(str(lca(a,b)))
print('\n'.join(output))
if __name__ == "__main__":
main()

Test details

Test 1

Verdict: ACCEPTED

input
10 10
1 2 3 4 5 6 7 8 9
6 9
8 10
10 3
...

correct output
6
8
3
1
8
...

user output
6
8
3
1
8
...

Test 2

Verdict: ACCEPTED

input
10 10
1 1 1 1 1 1 1 1 1
1 7
3 4
4 1
...

correct output
1
1
1
1
1
...

user output
1
1
1
1
1
...

Test 3

Verdict: ACCEPTED

input
10 10
1 1 1 1 2 3 4 4 1
1 8
2 7
8 3
...

correct output
1
1
1
1
1
...

user output
1
1
1
1
1
...

Test 4

Verdict: ACCEPTED

input
10 10
1 1 3 1 2 2 5 3 9
7 2
7 6
3 9
...

correct output
2
2
3
1
1
...

user output
2
2
3
1
1
...

Test 5

Verdict: ACCEPTED

input
10 10
1 2 3 2 5 3 2 2 4
6 1
1 3
1 9
...

correct output
1
1
1
2
2
...

user output
1
1
1
2
2
...

Test 6

Verdict:

input
200000 200000
1 2 3 4 5 6 7 8 9 10 11 12 13 ...

correct output
74862
8750
16237
72298
58111
...

user output
(empty)

Test 7

Verdict:

input
200000 200000
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

correct output
1
1
1
1
1
...

user output
(empty)

Test 8

Verdict:

input
200000 200000
1 2 1 2 3 2 1 6 3 1 10 12 13 4...

correct output
1
2
2
2
1
...

user output
(empty)

Test 9

Verdict:

input
200000 200000
1 2 3 4 5 6 7 8 9 10 11 12 13 ...

correct output
2796
633
633
151
2690
...

user output
(empty)

Test 10

Verdict:

input
200000 200000
1 2 3 4 5 6 7 8 9 10 11 12 13 ...

correct output
365
73
103
365
216
...

user output
(empty)

Test 11

Verdict: ACCEPTED

input
2 4
1
1 1
1 2
2 1
...

correct output
1
1
1
2

user output
1
1
1
2

Test 12

Verdict:

input
200000 200000
1 1 2 3 4 5 6 7 8 9 10 11 12 1...

correct output
27468
6353
27468
6353
6353
...

user output
(empty)