Task: | Dynamic Range Minimum Queries |
Sender: | laluj |
Submission time: | 2024-09-23 20:07:48 +0300 |
Language: | C++ (C++17) |
Status: | READY |
Result: | ACCEPTED |
test | verdict | time | |
---|---|---|---|
#1 | ACCEPTED | 0.00 s | details |
#2 | ACCEPTED | 0.44 s | details |
Code
#include <bits/stdc++.h> using namespace std; #define debug(x) cerr << #x << ": " << x << endl; int n; vector<int> tree; int minq(int a, int b) { a += n; b += n; int m = numeric_limits<int>::max(); while (a <= b) { if (a%2 == 1) m = min(m,tree[a++]); if (b%2 == 0) m = min(m,tree[b--]); a /= 2; b /= 2; } return m; } void update(int k, int x) { k += n; tree[k] = x; for (k /= 2; k >= 1; k /= 2) { tree[k] = min(tree[2*k],tree[2*k+1]); } } int main() { int q; cin >> n >> q; tree.resize(2*n); for (int i = 0; i < n; i++) { int x; cin >> x; update(i, x); } int queries[q][3]; for (int i = 0; i < q; i++) { cin >> queries[i][0] >> queries[i][1] >> queries[i][2]; } for (auto &&quer : queries) { if (quer[0] == 1) update(quer[1]-1, quer[2]); else cout << minq(quer[1]-1, quer[2]-1) << endl; } return 0; }
Test details
Test 1
Verdict: ACCEPTED
input |
---|
8 80 7 6 4 6 2 9 4 8 2 1 1 2 1 2 2 1 3 ... |
correct output |
---|
7 6 4 4 2 ... |
user output |
---|
7 6 4 4 2 ... Truncated |
Test 2
Verdict: ACCEPTED
input |
---|
200000 200000 398739055 65343131 699208332 3... |
correct output |
---|
28609 129890 20378 20378 311522 ... |
user output |
---|
28609 129890 20378 20378 311522 ... Truncated |