Task: | Dynamic Range Minimum Queries |
Sender: | Niilo |
Submission time: | 2024-09-19 10:55:05 +0300 |
Language: | C++ (C++17) |
Status: | READY |
Result: | ACCEPTED |
test | verdict | time | |
---|---|---|---|
#1 | ACCEPTED | 0.01 s | details |
#2 | ACCEPTED | 0.45 s | details |
Code
#include <bits/stdc++.h>using namespace std;using ll = long long;#define SEG_OP(a,b) min(a, b)struct Seg {static const int N = 1<<18;int S[N*2];Seg(int x = 0) {for (int i = N; i < N*2; ++i) S[i] = x;for (int i = N-1; i >= 1; --i) S[i] = SEG_OP(S[i*2], S[i*2+1]);}void set(int i, int x) {i |= N;S[i] = x;for (i /= 2; i >= 1; i /= 2) {S[i] = SEG_OP(S[i*2], S[i*2+1]);}}ll get(int a, int b, ll s = 0) {a |= N; b |= N;while (a <= b) {if (a % 2 == 1) s = SEG_OP(s, ll(S[a++]));if (b % 2 == 0) s = SEG_OP(s, ll(S[b--]));a /= 2; b /= 2;}return s;}};int n, q;Seg S( 1e9 );int main() {cin >> n >> q;for (int i = 0; i < n; ++i) {int x;cin >> x;S.set(i, x);}for (int i = 0; i < q; ++i) {int t, a, b;cin >> t >> a >> b;if (t == 1) {S.set(a-1,b);} else {cout << S.get(a-1,b-1, 1e9) << '\n';}}}
Test details
Test 1
Verdict: ACCEPTED
input |
---|
8 80 7 6 4 6 2 9 4 8 2 1 1 2 1 2 2 1 3 ... |
correct output |
---|
7 6 4 4 2 ... |
user output |
---|
7 6 4 4 2 ... Truncated |
Test 2
Verdict: ACCEPTED
input |
---|
200000 200000 398739055 65343131 699208332 3... |
correct output |
---|
28609 129890 20378 20378 311522 ... |
user output |
---|
28609 129890 20378 20378 311522 ... Truncated |