CSES - Aalto Competitive Programming 2024 - wk2 - Homework - Results
Submission details
Task:Connect cities
Sender:Farah
Submission time:2024-09-12 03:31:23 +0300
Language:C++ (C++11)
Status:READY
Result:ACCEPTED
Test results
testverdicttime
#1ACCEPTED0.00 sdetails
#2ACCEPTED0.00 sdetails
#3ACCEPTED0.00 sdetails
#4ACCEPTED0.00 sdetails
#5ACCEPTED0.00 sdetails
#6ACCEPTED0.14 sdetails
#7ACCEPTED0.14 sdetails
#8ACCEPTED0.14 sdetails
#9ACCEPTED0.14 sdetails
#10ACCEPTED0.14 sdetails
#11ACCEPTED0.17 sdetails
#12ACCEPTED0.01 sdetails

Code

#include <iostream>
#include <vector>

using namespace std;

// Union-Find (Disjoint Set Union) structure to manage connected components
class UnionFind {
public:
    vector<int> parent, rank;

    UnionFind(int n) {
        parent.resize(n + 1);
        rank.resize(n + 1, 0);
        for (int i = 1; i <= n; ++i) {
            parent[i] = i;
        }
    }

    int find(int u) {
        if (u != parent[u]) {
            parent[u] = find(parent[u]);  // Path compression
        }
        return parent[u];
    }

    void unite(int u, int v) {
        int root_u = find(u);
        int root_v = find(v);
        if (root_u != root_v) {
            if (rank[root_u] > rank[root_v]) {
                parent[root_v] = root_u;
            } else if (rank[root_u] < rank[root_v]) {
                parent[root_u] = root_v;
            } else {
                parent[root_v] = root_u;
                rank[root_u]++;
            }
        }
    }
};

int main() {
    int n, m;
    cin >> n >> m;

    UnionFind uf(n);

    // Read the roads and unite the connected cities
    for (int i = 0; i < m; ++i) {
        int a, b;
        cin >> a >> b;
        uf.unite(a, b);
    }

    // Find all the unique connected components
    vector<int> representatives;
    for (int i = 1; i <= n; ++i) {
        if (uf.find(i) == i) {
            representatives.push_back(i);
        }
    }

    // We need to connect (number of components - 1) roads
    int k = representatives.size() - 1;
    cout << k << endl;

    // Connect each pair of consecutive components
    for (size_t i = 1; i < representatives.size(); ++i) {
        cout << representatives[i - 1] << " " << representatives[i] << endl;
    }

    return 0;
}

Test details

Test 1

Verdict: ACCEPTED

input
10 10
2 5
5 6
1 4
6 8
...

correct output
2
1 2
2 7

user output
2
1 2
2 7

Test 2

Verdict: ACCEPTED

input
10 10
3 9
6 8
9 10
7 8
...

correct output
2
1 4
4 5

user output
2
4 5
5 6

Test 3

Verdict: ACCEPTED

input
10 10
7 9
1 7
1 3
3 4
...

correct output
0

user output
0

Test 4

Verdict: ACCEPTED

input
10 10
4 8
5 9
4 9
2 7
...

correct output
1
1 3

user output
1
3 4

Test 5

Verdict: ACCEPTED

input
10 10
4 9
2 4
7 10
1 8
...

correct output
0

user output
0

Test 6

Verdict: ACCEPTED

input
100000 200000
7233 22146
94937 96203
6133 10731
98737 99193
...

correct output
4785
1 2
2 3
3 4
4 5
...

user output
4785
1 3
3 11
11 14
14 17
...
Truncated

Test 7

Verdict: ACCEPTED

input
100000 200000
92950 93575
24401 88897
41796 99364
47106 50330
...

correct output
4868
1 2
2 7
7 9
9 15
...

user output
4868
1 7
7 9
9 15
15 16
...
Truncated

Test 8

Verdict: ACCEPTED

input
100000 200000
15637 76736
79169 98809
4382 86557
73383 77029
...

correct output
4683
1 9
9 20
20 27
27 28
...

user output
4683
9 20
20 27
27 28
28 33
...
Truncated

Test 9

Verdict: ACCEPTED

input
100000 200000
47932 66981
86401 99942
4353 27841
60492 67345
...

correct output
4807
1 6
6 7
7 11
11 12
...

user output
4807
6 7
7 11
11 12
12 30
...
Truncated

Test 10

Verdict: ACCEPTED

input
100000 200000
6554 44548
76413 98555
5447 59589
70166 74434
...

correct output
4786
1 2
2 18
18 21
21 27
...

user output
4786
18 21
21 27
27 28
28 29
...
Truncated

Test 11

Verdict: ACCEPTED

input
100000 1
1 2

correct output
99998
1 3
3 4
4 5
5 6
...

user output
99998
1 3
3 4
4 5
5 6
...
Truncated

Test 12

Verdict: ACCEPTED

input
10 9
2 5
5 6
1 4
6 8
...

correct output
2
1 2
2 7

user output
2
1 2
2 7