CSES - Aalto Competitive Programming 2024 - wk2 - Homework - Results
Submission details
Task:Connect cities
Sender:Mojojijo
Submission time:2024-09-09 12:35:15 +0300
Language:CPython3
Status:READY
Result:ACCEPTED
Test results
testverdicttime
#1ACCEPTED0.02 sdetails
#2ACCEPTED0.02 sdetails
#3ACCEPTED0.02 sdetails
#4ACCEPTED0.02 sdetails
#5ACCEPTED0.02 sdetails
#6ACCEPTED0.94 sdetails
#7ACCEPTED0.93 sdetails
#8ACCEPTED0.93 sdetails
#9ACCEPTED0.93 sdetails
#10ACCEPTED0.94 sdetails
#11ACCEPTED0.26 sdetails
#12ACCEPTED0.02 sdetails

Code

def connect_cities(n, roads):
    from collections import defaultdict
    import sys
    sys.setrecursionlimit(10**6)
     # Adjacency list
    graph = defaultdict(list)
    for a,b in roads:
        graph[a].append(b)
        graph[b].append(a)

    visited = [False] * (n+1)
    components =[]

    def dfs(node, component):
        visited[node] = True
        component.append(node)
        for neighbour in graph[node]:
            if not visited[neighbour]:
                dfs(neighbour, component)

    for i in range(1, n+1):
        if not visited[i]:
            component = []
            dfs(i, component)
            components.append(component)

    return components

def find_roads_to_add(n, roads):
    components = connect_cities(n, roads)
    
    # If there's only one component, no new roads are needed
    if len(components) == 1:
        print(0)
        return

    # We need to connect each component to the next one
    required_roads = []
    for i in range(len(components) - 1):
        # Connect the first city in component[i] to the first city in component[i+1]
        city1 = components[i][0]
        city2 = components[i+1][0]
        required_roads.append((city1, city2))
    
    # Step 5: Output the number of roads and the roads themselves
    print(len(required_roads))
    for road in required_roads:
        print(road[0], road[1])

n,m = map(int,input().split())

roads = []  
for _ in range(m):
    a,b = map(int,input().split())
    roads.append((a,b))

# print(roads)

find_roads_to_add(n, roads)

Test details

Test 1

Verdict: ACCEPTED

input
10 10
2 5
5 6
1 4
6 8
...

correct output
2
1 2
2 7

user output
2
1 2
2 7

Test 2

Verdict: ACCEPTED

input
10 10
3 9
6 8
9 10
7 8
...

correct output
2
1 4
4 5

user output
2
1 4
4 5

Test 3

Verdict: ACCEPTED

input
10 10
7 9
1 7
1 3
3 4
...

correct output
0

user output
0

Test 4

Verdict: ACCEPTED

input
10 10
4 8
5 9
4 9
2 7
...

correct output
1
1 3

user output
1
1 3

Test 5

Verdict: ACCEPTED

input
10 10
4 9
2 4
7 10
1 8
...

correct output
0

user output
0

Test 6

Verdict: ACCEPTED

input
100000 200000
7233 22146
94937 96203
6133 10731
98737 99193
...

correct output
4785
1 2
2 3
3 4
4 5
...

user output
4785
1 2
2 3
3 4
4 5
...

Test 7

Verdict: ACCEPTED

input
100000 200000
92950 93575
24401 88897
41796 99364
47106 50330
...

correct output
4868
1 2
2 7
7 9
9 15
...

user output
4868
1 2
2 7
7 9
9 15
...

Test 8

Verdict: ACCEPTED

input
100000 200000
15637 76736
79169 98809
4382 86557
73383 77029
...

correct output
4683
1 9
9 20
20 27
27 28
...

user output
4683
1 9
9 20
20 27
27 28
...

Test 9

Verdict: ACCEPTED

input
100000 200000
47932 66981
86401 99942
4353 27841
60492 67345
...

correct output
4807
1 6
6 7
7 11
11 12
...

user output
4807
1 6
6 7
7 11
11 12
...

Test 10

Verdict: ACCEPTED

input
100000 200000
6554 44548
76413 98555
5447 59589
70166 74434
...

correct output
4786
1 2
2 18
18 21
21 27
...

user output
4786
1 2
2 18
18 21
21 27
...

Test 11

Verdict: ACCEPTED

input
100000 1
1 2

correct output
99998
1 3
3 4
4 5
5 6
...

user output
99998
1 3
3 4
4 5
5 6
...

Test 12

Verdict: ACCEPTED

input
10 9
2 5
5 6
1 4
6 8
...

correct output
2
1 2
2 7

user output
2
1 2
2 7