Task: | Omenat |
Sender: | OOliOO |
Submission time: | 2016-01-23 23:44:08 +0200 |
Language: | C++ |
Status: | READY |
Result: | 0 |
group | verdict | score |
---|---|---|
#1 | TIME LIMIT EXCEEDED | 0 |
test | verdict | time | score | |
---|---|---|---|---|
#1 | TIME LIMIT EXCEEDED | -- | 0 | details |
#2 | TIME LIMIT EXCEEDED | -- | 0 | details |
#3 | TIME LIMIT EXCEEDED | -- | 0 | details |
#4 | TIME LIMIT EXCEEDED | -- | 0 | details |
#5 | TIME LIMIT EXCEEDED | -- | 0 | details |
#6 | TIME LIMIT EXCEEDED | -- | 0 | details |
#7 | TIME LIMIT EXCEEDED | -- | 0 | details |
#8 | TIME LIMIT EXCEEDED | -- | 0 | details |
#9 | TIME LIMIT EXCEEDED | -- | 0 | details |
#10 | TIME LIMIT EXCEEDED | -- | 0 | details |
Code
#include <iostream> #include <vector> #include <stack> #include <queue> #include <algorithm> #include <cmath> #include <iomanip> #include <unordered_set> #include <stdio.h> #include <string.h> #include <unordered_map> #include <fstream> #include <set> #include <map> #define MOD 1000000007 #define ll long long //#define N (1<<50) #define float double #define str string using namespace std; struct lol{ vector<int> o1,o2; ll diff; }; bool operator<(lol a, lol b){ if(a.diff==b.diff) return a.o1[0]<b.o1[0]; return a.diff<b.diff; } lol op(lol a, lol b){ if(a<b) return op(b,a); lol c; c.diff=a.diff-b.diff; for(auto asd:a.o1) c.o1.push_back(asd); for(auto asd:a.o2) c.o2.push_back(asd); for(auto asd:b.o1) c.o2.push_back(asd); for(auto asd:b.o2) c.o1.push_back(asd); return c; } lol op2(lol a, lol b){ lol c; c.diff=a.diff+b.diff; for(auto asd:a.o1) c.o1.push_back(asd); for(auto asd:a.o2) c.o2.push_back(asd); for(auto asd:b.o1) c.o1.push_back(asd); for(auto asd:b.o2) c.o2.push_back(asd); return c; } int vast[100]; lol parsa; set<lol> kek; int c; void etsi(ll js){ c++; if(c>=1000000) return; if(kek.size()==1){ if(kek.begin()->diff < parsa.diff) parsa=*kek.begin(); return; } lol a=*kek.rbegin(); kek.erase(a); lol b=*kek.rbegin(); kek.erase(b); if(js>2*a.diff){ lol c1=op2(a,b); kek.insert(c1); etsi(js); kek.erase(c1); } lol c2=op(a,b); kek.insert(c2); etsi(js-b.diff); kek.erase(c2); kek.insert(a); kek.insert(b); } int main(){ parsa.diff=1000000000000000000ll; int n; cin>>n; ll os=0; for(int i=0; i<n; i++){ lol uus; ll w; cin>>w; os+=w; uus.diff=w; uus.o1.push_back(i); kek.insert(uus); } /**while(pq.size()>=2){ lol a,b; a=pq.top(); pq.pop(); b=pq.top(); pq.pop(); pq.push(op(a,b)); }*/ etsi(os); for(int i:parsa.o1) vast[i]=1; for(int i:parsa.o2) vast[i]=2; for(int i=0; i<n; i++) cout<<vast[i]<<" "; return 0; }
Test details
Test 1
Verdict: TIME LIMIT EXCEEDED
input |
---|
95 779724552 231968220 985023789 ... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 2
Verdict: TIME LIMIT EXCEEDED
input |
---|
85 229722261 51722691 862338862 8... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 3
Verdict: TIME LIMIT EXCEEDED
input |
---|
97 398995377 989444445 634573915 ... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 4
Verdict: TIME LIMIT EXCEEDED
input |
---|
99 843687873 164010938 51269970 4... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 5
Verdict: TIME LIMIT EXCEEDED
input |
---|
90 864611617 418460939 773297829 ... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 6
Verdict: TIME LIMIT EXCEEDED
input |
---|
92 289890246 25801423 763027596 7... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 7
Verdict: TIME LIMIT EXCEEDED
input |
---|
89 879039800 50522278 850785072 4... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 8
Verdict: TIME LIMIT EXCEEDED
input |
---|
96 27192469 222283781 681532515 1... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 9
Verdict: TIME LIMIT EXCEEDED
input |
---|
100 186459081 254674429 394007236 ... |
correct output |
---|
(empty) |
user output |
---|
(empty) |
Test 10
Verdict: TIME LIMIT EXCEEDED
input |
---|
98 612168861 979831717 671087051 ... |
correct output |
---|
(empty) |
user output |
---|
(empty) |