CSES - Datatähti Open 2021 - Results
Submission details
Task:Distances
Sender:andr1y
Submission time:2021-01-30 15:02:54 +0200
Language:C++ (C++17)
Status:READY
Result:29
Feedback
groupverdictscore
#1ACCEPTED29
#20
Test results
testverdicttimegroup
#1ACCEPTED0.01 s1, 2details
#2--2details

Compiler report

input/code.cpp: In function 'int main()':
input/code.cpp:34:17: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
                 for(ll i = 1;i<=n;i++) cout<<p[i]<<' ';cout<<'\n';
                 ^~~
input/code.cpp:34:56: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
                 for(ll i = 1;i<=n;i++) cout<<p[i]<<' ';cout<<'\n';
                                                        ^~~~

Code

// -- //
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll N = 120;
vector<ll> d[N];
ll p[N];
ll dp[N][N], n;
void dfs(ll v, ll p, ll sv, ll len){
    dp[sv][v]=len;
    for(auto i : d[v]){
        if(i!=p) dfs(i, v, sv, len+1);
    }
}
signed main(){
	cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
    ll q;
    cin >> q;
    while(q--){
        cin >> n;
        for(ll i = 1;i<=n;i++) d[i].clear(), p[i]=i;
        for(ll a, b, i=1;i<n;i++){
            cin >> a >> b;
            d[a].push_back(b);
            d[b].push_back(a);
        }
        for(ll i = 1;i<=n;i++) dfs(i, -1, i, 0);
        do{
            bool ok =1;
            for(ll i = 2;i<=n;i++){
                ok=ok&&dp[p[i-1]][p[i]]<4;
            }
            if(ok){
                for(ll i = 1;i<=n;i++) cout<<p[i]<<' ';cout<<'\n';
                break;
            }
        }while(next_permutation(p+1, p+n+1));
    }
}

Test details

Test 1

Group: 1, 2

Verdict: ACCEPTED

input
100
8
5 2
2 3
3 7
...

correct output
1 8 2 5 6 7 3 4 
1 7 2 8 3 6 4 5 
1 4 6 2 7 5 8 3 
1 8 3 2 4 7 6 5 
1 6 4 7 5 2 3 8 
...

user output
1 3 2 4 7 5 6 8 
1 3 2 8 7 5 4 6 
1 3 2 5 7 8 6 4 
1 2 3 4 5 6 7 8 
1 3 2 4 6 8 7 5 
...
Truncated

Test 2

Group: 2

Verdict:

input
100
100
37 59
81 37
44 81
...

correct output
1 99 82 81 59 5 71 55 17 24 13...

user output
(empty)