Numerot

dp = [[[[(0,0)]*11 for i in range(11)] for k in range(11)] for j in range(30)]
done = [[[[False]*11 for i in range(11)] for k in range(11)] for j in range(30)]

def maxdigit(n):
    ans = 0
    while n > 0:
        ans = max(ans, n%10)
        n //= 10
    return ans

def solve(a,b,c,d):
    if done[a][b][c][d]:
        return dp[a][b][c][d]
    done[a][b][c][d] = True
    if a == 1:
        dp[a][b][c][d] = (0,d)
        return dp[a][b][c][d]
    if c == 1:
        if a == 2:
            val = 10+d
            cnt = 0
            while val >= 10:
                val -= max(b,maxdigit(val))
                cnt += 1
            dp[a][b][c][d] = (cnt,val)
            return dp[a][b][c][d]
        else :
            if b > d:
                p = solve(a-1,9,1,10+d-b-1)
                pp = solve(a-1,b,9,p[1])
                dp[a][b][c][d] = (p[0] + pp[0], pp[1])
                return dp[a][b][c][d]
            else:
                x = max(1,b)
                p = solve(a-1,9,1,10-x-1)
                pp = solve(a-1,b,9,p[1])
                lisa = 0
                if d > 0:
                    lisa += 1
                dp[a][b][c][d] = (p[0] + pp[0] + lisa, pp[1])
                return dp[a][b][c][d]
    else:
        kaytossa = max(b,c)
        if b >= c or a == 2:
            p = solve(a,kaytossa,1,d)
            pp = solve(a,b,c-1,p[1])
            dp[a][b][c][d] = (p[0] + pp[0], pp[1])
            return dp[a][b][c][d]
        else:
            if c > d:
                p = solve(a,c-1,1,d-1)
                pp = solve(a,b,c-1,p[1])
                dp[a][b][c][d] = (p[0] + pp[0], pp[1])
                return dp[a][b][c][d]
            else:
                p = solve(a,b,c,0)
                dp[a][b][c][d] = (p[0] + 1, p[1])
                return dp[a][b][c][d]
            
def ratkaise(x):
    n = len(x)
    prefmax = [0]*(n+1)
    prefmax[0] = ord(x[0]) - ord('0')
    for i in range(1,n):
        prefmax[i] = max(prefmax[i-1], ord(x[i]) - ord('0'))
    ans = 0
    digit = ord(x[n-1]) - ord('0')
    ind = 1
    for i in range(n-1,-1,-1):
        numero = ord(x[i]) - ord('0')
        if numero != 0:
            maxi = 0
            if i > 0:
                maxi = prefmax[i-1]
            p = dp[ind][maxi][numero][digit]
            ans += p[0]
            digit = p[1]
        ind += 1
    return ans + 1

for i in range(1,23):
    for j in range(10):
        for k in range(1,10):
            for l in range(10):
                solve(i,j,k,l)
                
                

t = int(input())
for i in range(t):
    a = int(input())
    x = 0
    for i in range(67,-1,-1):
        if ratkaise(str(x+(1<<i))) < a:
            x |= (1<<i)
    print(x+1)

Test 1

Group: 1, 2, 3

Verdict: ACCEPTED

Test 2

Group: 2, 3

Verdict: ACCEPTED

Test 3

Group: 3

Verdict: TIME LIMIT EXCEEDED