Task: | Kyselyt |
Sender: | Shrike |
Submission time: | 2017-10-03 11:04:09 +0300 |
Language: | C++ |
Status: | READY |
Result: | 0 |
group | verdict | score |
---|---|---|
#1 | TIME LIMIT EXCEEDED | 0 |
#2 | TIME LIMIT EXCEEDED | 0 |
#3 | TIME LIMIT EXCEEDED | 0 |
test | verdict | time | group | |
---|---|---|---|---|
#1 | TIME LIMIT EXCEEDED | -- | 1 | details |
#2 | TIME LIMIT EXCEEDED | -- | 2 | details |
#3 | TIME LIMIT EXCEEDED | -- | 3 | details |
Code
#include <iostream>#include <cmath>using namespace std;typedef long long ll;lldecade(ll n, ll *sum){*sum = 0;for (int i = 1; i < 1000000; i++) {if (*sum + i*9*pow(10.0, i-1) > n)return i;else*sum += i*9*pow(10.0, i-1);}return 0;}llnnum(ll dec, ll nth){return (ll)(pow(10.0, (int)dec-1)-1+nth);}int dig(int a, int b) {int i, digit;digit = 1;for(i = b-1; i > 0; i++)digit = digit*10;digit = (a/digit) % 10;return digit;}intmain(int argc, char **argv){ios_base::sync_with_stdio(0);cin.tie(0);int q;cin >> q;ll qs[q];for (int i = 0; i < q; i++) {cin >> qs[i];ll inth, nth, dec, s, sm, num;dec = decade(qs[i], &s);sm = qs[i] - s;nth = (ll)ceil((double)sm/(double)dec);inth = nth % dec;num = nnum(dec, nth);cout << dig((int)num, inth+1) << "\n";}return 0;}
Test details
Test 1
Group: 1
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 582 214 723 273 ... |
correct output |
---|
0 1 7 7 6 ... |
user output |
---|
(empty) |
Test 2
Group: 2
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 615664 916441 627600 279508 ... |
correct output |
---|
1 2 3 2 2 ... |
user output |
---|
(empty) |
Test 3
Group: 3
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 672274832941907421 260504693279721732 646999966092970935 100853063389774434 ... |
correct output |
---|
7 2 2 0 9 ... |
user output |
---|
(empty) |