Task: | Kyselyt |
Sender: | Shrike |
Submission time: | 2017-10-03 11:00:24 +0300 |
Language: | C++ |
Status: | READY |
Result: | 0 |
group | verdict | score |
---|---|---|
#1 | TIME LIMIT EXCEEDED | 0 |
#2 | TIME LIMIT EXCEEDED | 0 |
#3 | TIME LIMIT EXCEEDED | 0 |
test | verdict | time | group | |
---|---|---|---|---|
#1 | TIME LIMIT EXCEEDED | -- | 1 | details |
#2 | TIME LIMIT EXCEEDED | -- | 2 | details |
#3 | TIME LIMIT EXCEEDED | -- | 3 | details |
Code
#include <iostream> #include <cmath> using namespace std; typedef long long ll; ll decade(ll n, ll *sum) { *sum = 0; for (int i = 1; i < 1000000; i++) { if (*sum + i*9*pow(10.0, i-1) > n) return i; else *sum += i*9*pow(10.0, i-1); } return 0; } ll nnum(ll dec, ll nth) { return (ll)(pow(10.0, (int)dec-1)-1+nth); } int dig(int a, int b) { int i, digit; digit = 1; for(i = b-1; i > 0; i++) digit = digit*10; digit = (a/digit) % 10; return digit; } int main(int argc, char **argv) { int q; cin >> q; ll qs[q]; for (int i = 0; i < q; i++) { cin >> qs[i]; } for (int i = 0; i < q; i++) { ll inth, nth, dec, s, sm, num; dec = decade(qs[i], &s); sm = qs[i] - s; nth = (ll)ceil((double)sm/(double)dec); inth = nth % dec; num = nnum(dec, nth); cout << dig((int)num, inth+1) << endl; } return 0; }
Test details
Test 1
Group: 1
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 582 214 723 273 ... |
correct output |
---|
0 1 7 7 6 ... |
user output |
---|
(empty) |
Test 2
Group: 2
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 615664 916441 627600 279508 ... |
correct output |
---|
1 2 3 2 2 ... |
user output |
---|
(empty) |
Test 3
Group: 3
Verdict: TIME LIMIT EXCEEDED
input |
---|
1000 672274832941907421 260504693279721732 646999966092970935 100853063389774434 ... |
correct output |
---|
7 2 2 0 9 ... |
user output |
---|
(empty) |